All categories

3 years ago

Find an equation of the plane that contains (3, 4, −9) and is parallel to x + y − 5z = 1. (Use x, y, and z for coordinates.)

Mathematics

1 answer:

emmainna [20.7K]3 years ago

6 0

Answer:

x + y - 5z = 52

Step-by-step explanation:

Given data:

Point on the plane (3,4,-9)

parallel to x + y -5z = 1

Finding the normal vector

(1 , 1 , -5)(x, y , z) = 1

the normal vector is (1 , 1 , -5)

formula for finding equation the plane given the normal vector (a,b,c) and point (m,n,o) is as

a(x - m) + b(y - n) + c(z-o)=0

Substituting the data we have

1(x-3) + 1( y- 4) - 5(z+9) =0

x-3 +y -4 -5z -45 = 0

x + y - 5z = 45 +4 +3

x + y - 5z = 52

You might be interested in

Bradley and his family drove to visit a museum. They drove 9/25 of the way and stopped for gasoline. Write the fraction of the d

labwork [276]

The answer is 0.36.

Hope this helped! :)

5 0

3 years ago

Read 2 more answers

PLEASE HELP ASAP! Also please check the ones I have already done, if it’s wrong please tell me the answers too! Thanks you soo m

mario62 [17]

I’m sorry I’m on a time crunch I wish I could help you with all of them! But I check the first 3 ones and they are correct amazing job have a wonderful day ☺️❤️

4 0

3 years ago

Read 2 more answers

Ari stocks shelves at a grocery store.He puts 35 cans of juice in each display case.The case has 4 shelves with an equal number

ICE Princess25 [194]

Answer:

There are 8 cans on each of the equal shelves

Step-by-step explanation:

Total number of cans put in display = 35

Shelves with equal no of cans = 4 Shelves

And one shelf displays only 3 cans

Therefore, 4 shelves with equal no of cans + 1 shelf with 3 cans = 35 cans

Let us assume equal no. of cans be x

We get, 4x + 3 = 35

4x = 35 - 3

4x = 32

x = 32 ÷ 4

x = 8

Thus, 4 shelves with equal no of cans contains 8 cans each.

6 0

3 years ago

Solve this simultaneous equation by using substitution method 3x-2y=12 and x+3y=-7

ratelena [41]

Answer:

Solving this simultaneous equation by using substitution method 3x-2y=12 and x+3y=-7 we get x=2 and y=-3

Solution set = {2,-3}

Step-by-step explanation:

We need to solve this simultaneous equation by using substitution method 3x-2y=12 and x+3y=-7

let:

$3x-2y=12--eq(1)\\x+3y=-7 --eq(2)$

Finding value of x from equation 2 and putting in eq(1)

$From \ eq(2)\\x+3y=-7\\x=-7-3y$

Putting value of x in eq(1)

$3x-2y=12\\Put \ x=-7-3y\\3(-7-3y)-2y=12\\Solving\\-21-9y-2y=12\\-11y=12+21\\-11y=33\\y=\frac{33}{-11}\\y=-3$

So, we get y=-3

Now put value of y in equation 2 to find value of x

$x+3y=-7\\x+3(-3)=-7\\x-9=-7\\x=-7+9\\x=2$

So, we get value of x =2

So, solving this simultaneous equation by using substitution method 3x-2y=12 and x+3y=-7 we get x=2 and y=-3

Solution set = {2,-3}

4 0

3 years ago

Find the equivalent fraction for 10/20

dezoksy [38]

$\frac{10}{20} = \frac{ \frac{10}{10} }{ \frac{20}{10} } = \frac{1}{2}$

6 0

3 years ago