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ycow [4]
2 years ago
14

Find an equation of the plane that contains (3, 4, −9) and is parallel to x + y − 5z = 1. (Use x, y, and z for coordinates.)

Mathematics
1 answer:
emmainna [20.7K]2 years ago
6 0

Answer:

x + y - 5z = 52

Step-by-step explanation:

Given data:

Point on the plane (3,4,-9)

parallel to x + y -5z = 1

Finding the normal vector

(1 , 1 , -5)(x, y , z) = 1

the normal vector is (1 , 1 , -5)

<em>formula for finding equation the plane given the normal vector (a,b,c) and point (m,n,o) is as </em>

<em>a(x - m) + b(y - n) + c(z-o)=0</em>

Substituting the data we have

1(x-3) + 1( y- 4) - 5(z+9) =0

x-3 +y -4 -5z -45 = 0

x + y - 5z = 45 +4 +3

x + y - 5z = 52

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Use the distributive property of multiplication to find 5×45.<br> Hint: 45=5+40.
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Answer:

Step-by-step explanation:

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