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Evgesh-ka [11]
3 years ago
13

Find the area and perimeter of parallelogram.

Mathematics
1 answer:
kotegsom [21]3 years ago
4 0

Answer:

2 * 4  then repeat

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The volume, v, of a solid is v = bh, where b is the area of the base and h is the height.solve v = bh for h.
notsponge [240]
V = bh....divide both sides by b
v/b = h <===
3 0
3 years ago
Nick is saving money to buy a new skateboard and gear, and he needs to save more than $190.44 in order to have enough. Nick has
Dominik [7]

Answer:

Your answer is $19.53 per week.

8 0
1 year ago
Simplify. Use the distributive property. 5(3x+1)​
vlada-n [284]

Answer:

15x+5

Step-by-step explanation:

First you distribute the 5 to the 3x ( 5 times 3x=15x)

Next you distribute the 5 to the 1 (5 times 1=5)

Finally you put the two answers together 15x+1

you cant simplify it anymore because you cannot add 15x to 1

6 0
3 years ago
Elasticity of Demand The demand function for a certain brand of backpacks is
Trava [24]

Answer:

See explanation

Step-by-step explanation:

Solution:-

- The demand function of a certain brand is given as price P a function of x quantity of goods ( in hundred ) demanded per month. The relation is:

                           P ( x ) = 50 Ln ( 50 / x ).

- The point price elasticity ( E ) of demand is given by:

                           E = \frac{P}{x}*\frac{dP}{dx}  

- Where, dP / dx : is the rate of change of price ( P ) with each hundred unit of good ( x ) is demanded.

- To determine the " dP / dx " by taking the first derivative of the given relation:

                          P ( x ) = 50 Ln ( 50 / x ).

                          d P ( x ) / dx = [ 50*x / 50 ] * [ -1*50 / x^2 ]

                                              = - 50 / x

- Hence the point price elasticity of demand is given by:

                          E = - ( P / x ) * ( 50 / x )

                          E = -50*P / x^2    

- For an inelastic demand, ! E ! is < 1:

                          ! -50*P / x^2 ! < 1

                          50*P / x^2 < 1

                          P < x^2 / 50

- For an unitary demand, ! E ! is =  1:

                          ! -50*P / x^2 !  = 1

                          50*P / x^2 = 1

                          P = x^2 / 50

- For an inelastic demand, ! E ! is > 1:

                          ! -50*P / x^2 ! > 1

                          50*P / x^2 > 1

                          P > x^2 / 50

2)

If the unit price is increased slightly from $50, will the revenue increase or decrease?

- We see from the calculated demand sensitivity d P / dt:

                          d P ( x ) / dx = - 50 / x

- We see that as P increases the from P = $50, the quantity of goods demanded would be:

                          50 = 50 ln(50/x)

                           1 = Ln ( 50 / x )

                           50/x = e

                           x = 50 / e

Then,

                          d P ( x ) / dx = - 50 / ( 50 / e )

                          d P ( x ) / dx = - e

- We see that if price slightly increases from $ 50 then the quantity demanded would decrease by e (hundreds ) goods.

- The decrease in the quantity demanded is higher than the increase in price. The revenue is given by the product of price P ( x ) and x:

                Revenue R ( x ) = P ( x ) * x

                                = 50*x*ln(50/x)

Then the product of price and quantity goods also decreases; hence, revenue decreases.

8 0
3 years ago
Let $f$ be a function such that $f(x+y) = x + f(y)$ for any two real numbers $x$ and $y$. if $f(0) = 2$, then what is $f(2012)?$
marusya05 [52]

<span>Given:

f(0) = 2</span>

So first of all, we let x = 2012, y = 0: 

<span>
Then, F(2012) = 2012 + f(0)

Since f(0) = 2, then f(2012) = 2012 + 2 = 2014.

To add, </span>the process that relates an input to an output is called a function.

 

 

<span>There are always three main parts of a function, namely:

</span>Input

The Relationship

The Output

 

The classic way of writing a function is "f(x) = ... ".

 

What goes into the function is put inside parentheses () after the name of the function: So, f(x) shows us the function is called "f", and "x" goes in.

 

 

What a function does with the input can be usually seen as:

 

<span>f(x) = x2</span><span> reveals to us that function "f" takes "x<span>" and squares it.</span></span>

3 0
3 years ago
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