Answer:
4.88 x 10∧-8 sec
Explanation:
Part A
1 answer:
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Answer:
The electric charge, q (in coulomb units) = 5004 C
Given:
The charge stored as printed on NiMH battery, q = 1390 mAh
Solution:
To express the amount of electric charge printed on the battery in milli-ampere-hour (mAh) in coulomb, we will do simple conversion of milli amperes in ampere and hours in seconds:
1 mA =
1 hour =
Also, we know that the rate of flow of charge is electric current, I:
I =
⇒ q = [tex]I\times t[tex] (1)
where
q = electric charge
I = current
t = time taken for flow of current
Using eqn(1), we get:
q = [tex]1390\times 10^{-3}\times 60\times 60[tex]
q = 5004 A-s = 5004 C
Answer:
The answer to your question is 75 cm²
Explanation:
To solve this problem, we need to use the Pascal's principle that states that the pressure in a point is equal to the pressure in a second point.
Process
1.- Solve for A2
2.- Substitution
3.- Simplification and result
A2 = 75 cm²
Answer:
Speed of second car will be 57.17 m/sec
Explanation:
We have given lead car travels = 44 laps
1 laps = 1.34 km = 1340 m
So total distance = 1340×44 = 58960 m
Speed of lead car = 55.9 m/sec
We know that
As the second car is 1 lap behind so distance traveled by second car = 45×1340 = 60300 m
So speed of second car will be