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grin007 [14]
3 years ago
14

What is the current through a 11v bulb with a power of 99w

Physics
1 answer:
Murrr4er [49]3 years ago
8 0

Answer:

9.01amp

Explanation:

Power = V^2/R

Given that v = 11volts, P = 99watts

99 = 11^2/R

11×11 = 99R

121= 99R

R = 121/99

R= 1.22ohms

From ohms Law; V = IR

11volts = I × 1.22ohms

I = 11/1.23

I = 9.01 amp

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Which of these reactions is responsible for energy radiating from stars, including the Sun?
snow_tiger [21]

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3 years ago
Three points A, B, and C of unknown charges are at the corners of an equilateral triangle.
nasty-shy [4]
Answer: option d. 

Q_A= \frac{1}{2} Q_B=- \frac{1}{3} Q_C

Explanation:


1) The direction of the field lines inform about the sign of the charges.

The field lines <span>extend from the positive charges to the negative charges, so you can conclude that the charge C is positve and both charge A and charge B are negative:
</span><span>
</span><span>
</span><span>Charge C: positive
</span><span>
</span><span>Charge A: negative
</span><span>
</span><span>Charge B: netative
</span>

2) The density of the lines (number of lines in a region) inform about the magnitude of the electric field.

Since the charges are at the same distance, the magnitude of the electric field informs directly about the magnitude of the force and that about the magnitude of the charges.

Since, there are the double of lines between C and B than between C and A, the magnitude of charge B is the double than the magnitud of charge A.

From the five options given (a throug e) the only that is consistent with that charges A and B have the same sign, that charge C has different sign, and that charge B is the double of charge A is:

Q_A= \frac{1}{2} Q_B=- \frac{1}{3} Q_C
3 0
3 years ago
Someone drops a brick on a 2.6 kg cart moving at 28.2 cm/s. After the collision, the dropped brick and cart are moving together
Softa [21]

Answer:

2.087 kg

Explanation:

From the law of conservation of momentum,

Total momentum before collision = total momentum after collision.

MU + mu = V(M+m)............................ Equation 1

Where M = mass of  the cart, m = mass of the brick, U = initial velocity of the cart, u = initial velocity of the brick, V = velocity of both cart and brick after collision.

Note: The initial velocity of the brick is zero Thus mu = 0

making m the subject of the equation,

m =(MU/V)-M ........................................ Equation 2

Given: M = 2.6 kg, U = 28.2 cm/s = 0.283 m/s, V = 15.7 cm/s = 0.157 m/s.

Substituting into equation 2,

m = (2.6×0.283/0.157)-2.6

m = 2.087 kg

Thus the mass of the brick = 2.087 kg

5 0
3 years ago
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