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Oksanka [162]
3 years ago
14

A golfer hits a golf ball with a velocity of 36.0 meters/second at an angle of 28.0°. If the hang time of the golf ball is 3.44

seconds, what is the range of the golf ball?
Physics
1 answer:
Ray Of Light [21]3 years ago
5 0
Solving this using the time, we know that range = horizontal velocity x time of flight 

<span>since there are no horizontal forces acting on the ball, there are no horizontal accelerations and the initial horizontal velocity of 36 cos 28 will be constant throughout. I</span><span>f we use the correct time of flight given the launch parameters, we have </span>

<span>range = 36 cos 28 x 3.44 s = 109.3 m </span>
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A thermally isolated system is made up of a hot piece of aluminum and a cold piece of copper; the aluminum and the copper are in
butalik [34]

Answer:

copper will have more change in temperature as compare with aluminum

Explanation:

Hot piece of copper is made in contact with cold piece of aluminium

So here thermal energy transfer will take place from copper to aluminium

so by energy conservation we can say that heat given by copper is same as the heat absorbed by aluminium.

now we have

m_1s_1\Delta T_1 = m_2s_2\Delta T_2

here we know that

s_1 = specific heat capacity of copper

s_2 = specific heat capacity of aluminum

given that specific heat capacity of aluminium is more than double that of copper

so we can say

s_2 = 2s_1

so here if the mass of copper and aluminium is same then

\Delta T_1 = 2 \Delta T_2

so temperature change of copper is twice the temperature change of aluminium

So copper will have more change in temperature as compare with aluminum

4 0
3 years ago
During a very quick stop, a car decelerates at 7.6 m/s2. Assume the forward motion of the car corresponds to a positive directio
Mashcka [7]

Answer:

24.57 revolutions

Explanation:

(a) If they do not slip on the pavement, then the angular acceleration is

\alpha = a / r = 7.6 / 0.26 = 29.23 rad/s^2

(b) We can use the following equation of motion to find out the angle traveled by the wheel before coming to rest:

\omega^2 - \omega_0^2 = 2\alpha\Delta \theta

where v = 0 m/s is the final angular velocity of the wheel when it stops, \omega_0 = 95rad/s is the initial angular velocity of the wheel, \alpha = -29.23 rad/s^2 is the deceleration of the wheel, and \Delta \theta is the angle swept in rad, which we care looking for:

0 - 95^2 = 2*29.23\Delta \theta

9025 = 58.46 \Delta \theta

\Delta \theta = 9025 / 58.46 = 154.375 rad

As each revolution equals to 2π, the total revolution it makes before stop is

154.375 / 2π = 24.57 revolutions

8 0
2 years ago
At which of the following temperature and pressure levels would a gas be most likely to follow the ideal gas law? A. 0 K and 100
bulgar [2K]
The Ideal Gas Law makes a few assumptions from the Kinetic-Molecular Theory. These assumptions make our work much easier but aren't true under all conditions. The assumptions are,

1) Particles of a gas have virtually no volume and are like single points.
2) Particles exhibit no attractions or repulsions between them.
3) Particles are in continuous, random motion.
4) Collisions between particles are elastic, meaning basically that when they collide, they don't lose any energy.
5) The average kinetic energy is the same for all gasses at a given temperature, regardless of the identity of the gas.

It's generally true that gasses are mostly empty space and their particles occupy very little volume. Gasses are usually far enough apart that they exhibit very little attractive or repulsive forces. When energetic, the gas particles are also in fairly continuous motion, and without other forces, the motion is basically random. Collisions absorb very little energy, and the average KE is pretty close.

Most of these assumptions are dependent on having gas particles very spread apart. When is that true? Think about the other gas laws to remember what properties are related to volume.

A gas with a low pressure and a high temperature will be spread out and therefore exhibit ideal properties.

So, in analyzing the four choices given, we look for low P and high T.

A is at absolute zero, which is pretty much impossible, and definitely does not describe a gas. We rule this out immediately.

B and D are at the same temperature (273 K, or 0 °C), but C is at 100 K, or -173 K. This is very cold, so we rule that out.

We move on to comparing the pressures of B and D. Remember, a low pressure means the particles are more spread out. B has P = 1 Pa, but D has 100 kPa. We need the same units to confirm. Based on our metric prefixes, we know that kPa is kilopascals, and is thus 1000 pascals. So, the pressure of D is five orders of magnitude greater! Thus, the answer is B.
6 0
3 years ago
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Anton [14]

The answer is C conduction

7 0
2 years ago
Read 2 more answers
Which vector best represents the force that could act concurrently with force A to produce force B
viva [34]
Chose answer 2

cheers

8 0
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