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Oksanka [162]
3 years ago
14

A golfer hits a golf ball with a velocity of 36.0 meters/second at an angle of 28.0°. If the hang time of the golf ball is 3.44

seconds, what is the range of the golf ball?
Physics
1 answer:
Ray Of Light [21]3 years ago
5 0
Solving this using the time, we know that range = horizontal velocity x time of flight 

<span>since there are no horizontal forces acting on the ball, there are no horizontal accelerations and the initial horizontal velocity of 36 cos 28 will be constant throughout. I</span><span>f we use the correct time of flight given the launch parameters, we have </span>

<span>range = 36 cos 28 x 3.44 s = 109.3 m </span>
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