Solving this using the time, we know that range = horizontal velocity x time of flight
<span>since there are no horizontal forces acting on the ball, there are no horizontal accelerations and the initial horizontal velocity of 36 cos 28 will be constant throughout. I</span><span>f we use the correct time of flight given the launch parameters, we have </span>
<span>range = 36 cos 28 x 3.44 s = 109.3 m </span>
