Answer:
Step-by-step explanation:
Given:
--- Position
--- Change
Required
Find the new position
The new position is calculated as:
The first term of this sequence is -20, and the common ratio is 11. Thus, the formula for the nth term is
a(n) = a(1)*(11)^(n-1), or (-20)*(11)^(n-1).
Thus, the 12th term is
a(12) = (-20)*(11)^(12-1) = -20(11)^11 = -20(2.85 times 10 to the 11th power.
or ... -5.71 times 10 to the 12th power.
Answer:
B) To represent the distance between 3 and −5 on a number line, the correct expression is I(3) - (-5)I .
Step-by-step explanation:
Here the point A is given as 3 on number line.
Point B is given as -5 on number line.
To find : IA-BI
The distance between any two point A and B is given as IA-BI.
Now, to find the absolute value:
IA-BI = I (3) - (-5)I
or, IA-BI = I (3) + 5I = I8I
= 8 units
or, IA-BI = 8 units
Hence, on the number line, the distance between -5 and 3 is 8 units.
And, to represent the distance between 3 and −5 on a number line, the correct expression is I(3) - (-5)I .
Answer:
43.96
Step-by-step explanation:
14 x 3.14 = 43.96
7 is the radius but 14 is the like line and to find it you add 7 plus 7 (aka the other half) and multiply it by 3.14 thus the answer is
43.96
9514 1404 393
Answer:
the difference of 2 or 3 rectangles
Step-by-step explanation:
In every case, the "shaded" area can be computed by finding the area of a "bounding" rectangle, and subtracting the areas of the rectangular cutouts that give the figure its shape.
(a) The cutout is the white space at upper right. (Insufficient dimensions are given.)
(b) The cutout is the white space at lower left. The bounding rectangle is 8×7, and the cutout is 4×3.
(c) The cutout is the rectangle in the middle. The bounding rectangle is 13×7, and the cutout is 4×1.
(d) The cutouts are the rectangles on either side. They could be considered as a single unit. The bounding rectangle is 20×25; the cutouts have a total width of 16 and a height of 20, so total 16×20.
(e) Similar to (d), the cutouts are the white spaces on either side. The bounding rectangle is 14×12. The cutouts total 12 in width and 3 in height, so total 12×3.
__
You will note in (d) and (e) that the dimensions of the cutouts have something in common with the dimensions of the bounding rectangle. This means the problem can be simplified a little bit by factoring out that common factor. In (e), for example, 14×12 -(12×3) = 12(14 -3) = 12×11
