Christopher wrote the number pattern below. The first term is 8.

Please help with number 7! :D please and thank you!

schepotkina [342]

Answer:

fraction

Step-by-step explanation:

any number between 0 and 1 is a fraction

3 0

3 years ago

Cynthia wants to multiply 0.8 by a fraction less than 1. How will the product compare to 0.8? It will be 0.8.

BartSMP [9]

Answer:

Step-by-step explanation:

8 0

3 years ago

One rectangle has a base of 12 inches and an altitude of 6inches, The other has a base of 10 inches and an altitude of 5 inches.

liubo4ka [24]

Sides of first rectangle are 12 inches and 6 inches

and sides of second rectangle are 10 inches and 5 inches

So to find the ration of sides we can do

Ratio of bases = 12/10 = 6/5

Ratio of altitudes = 6/5

Area of first rectangle = base * altitude = 12 *6 = 72 square inches

6 0

3 years ago

Given: △ABC, m∠A=60° m∠C=45°, AB=8 Find: Perimeter of △ABC, Area of △ABC . FIRST CORRECT ANSWER GETS POINTS AND BRAINLIEST!!!! T

Ad libitum [116K]

Answer:

Given : In △ABC, m∠A=60°, m∠C=45°,and AB=8 unit

Firstly, find the angles B

Sum of measures of the three angles of any triangle equal to the straight angle, and also expressed as 180 degree

∴m∠A+ m∠B+m∠C=180 ......[1]

Substitute the values of m∠A=60° and m∠C=45° in [1]

$60^{\circ}+ m\angle B+45^{\circ}=180^{\circ}$

$105^{\circ}+ m\angle B=180^{\circ}$

Simplify:

$m\angle B=75^{\circ}$

Now, find the sides of BC

For this, we can use law of sines,

Law of sine rule is an equation relating the lengths of the sides of a triangle to the sines of its angles.

$\frac{\sin A}{BC} = \frac{\sin C}{AB}$

Substitute the values of ∠A=60°, ∠C=45°,and AB=8 unit to find BC.

$\frac{\sin 60^{\circ}}{BC} =\frac{\sin 45^{\circ}}{8}$

then,

$BC = 8 \cdot \frac{\sin 60^{\circ}}{\sin 45^{\circ}}$

$BC=8 \cdot \frac{0.866025405}{0.707106781} =9.798$ unit

Similarly for AC:

$\frac{\sin B}{AC} = \frac{\sin C}{AB}$

Substitute the values of ∠B=75°, ∠C=45°,and AB=8 unit to find AC.

$\frac{\sin 75^{\circ}}{AC} =\frac{\sin 45^{\circ}}{8}$

then,

$AC = 8 \cdot \frac{\sin 75^{\circ}}{\sin 45^{\circ}}$

$AC=8 \cdot \frac{0.96592582628}{0.707106781} =10.9283$ unit

To find the perimeter of triangle ABC;

Perimeter = Sum of the sides of a triangle

i,e

Perimeter of △ABC = AB+BC+AC = 8 +9.798+10.9283 = 28.726 unit.

To find the area(A) of triangle ABC ;

Use the formula:

$A = \frac{1}{2} \times AB \times AC \times \sin A$

Substitute the values in above formula to get area;

$A=\frac{1}{2} \times 8 \times 10.9283 \times \sin 60^{\circ}$

$A = 4 \times 10.9283 \times 0.86602540378$

Simplify:

Area of triangle ABC = 37.856 (approx) square unit

4 0

3 years ago

Verify that your point from Question 2 is a solution to 2x-y=-12x−y=−1 AND is also a solution to y=5x-5y=5x−5. What does it mean

Vera_Pavlovna [14]

Answer:

(a) Verified

(b) They are simultaneous equations

Step-by-step explanation:

Given

$2x - y = -1$

$y =5x - 5$

Required

Verify that: $(x,y) = (2,5)$ is a solution

We have:

$2x - y = -1$

Substitute: $(x,y) = (2,5)$

$2 * 2 - 5 = -1$

Evaluate all products

$4 - 5 = -1$

Subtract:

$-1 = -1$

Because both sides of the equation are equal, then the point is a solution

Also: $y =5x - 5$

Substitute: $(x,y) = (2,5)$

$5 = 5 * 2 - 5$

Evaluate all products

$5 = 10 - 5$

Subtract:

$5 = 5$

Because both sides of the equation are equal, then the point is a solution

Because the given point is a solution to both equations, then they are simultaneous equation

7 0

3 years ago