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dolphi86 [110]
3 years ago
5

The height (h) of a fireball launched from a Roman candle with an initial velocity of 64 feet per second is given by the equatio

n h(t) = -16t^2 + 64t, where t is time in seconds after launch. Use the graph of this function to answer the questions. Estimate the time when the fireball is at its maximum height.
A. 2.3 seconds

B. 2 seconds

C. 0 seconds

D. 4 seconds
Mathematics
1 answer:
Zigmanuir [339]3 years ago
3 0

Answer: C or 2 seconds.

Step-by-step explanation:

To find the vertex in a standard form equation: (-b/2a,f(-b/2a))

plug it in: -64/2*-32 = 2

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2 years ago
JKLM is a rhombus. KM is 20 and JL is 48. Find the perimeter of the<br><br> rhombus.
anygoal [31]

Answer:

104 units

Step-by-step explanation:

Given

Shape: Rhombus

JL = 48

KM = 20

Required

Determine the perimeter

The given parameter are the diagonals of the rhombus.

The perimeter (from diagonals) is calculated as thus:

P = 2\sqrt{(JL)^2 + (KM)^2}

Substitute values for JL and KM

P = 2\sqrt{48^2 + 20^2}

P = 2\sqrt{2304 +400}

P = 2\sqrt{2704}

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<em>Hence, the perimeter is 104 units</em>

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2 years ago
I need help ill give brainiest
Gnoma [55]

Answer:

9 ft

Step-by-step explanation:

its volume is equal to the area by height;

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h = 9ft

5 0
3 years ago
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IrinaK [193]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
Solve (x + 5)2 = 48.
natita [175]

Answer:

x = -5  ±4sqrt(3)

Step-by-step explanation:

(x + 5)^2 = 48

Take the square root of each side

sqrt((x + 5)^2) = ±sqrt(48)

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x+5 = ±4sqrt(3)

Subtract 5 from each side

x = -5  ±4sqrt(3)

7 0
3 years ago
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