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dolphi86 [110]
3 years ago
5

The height (h) of a fireball launched from a Roman candle with an initial velocity of 64 feet per second is given by the equatio

n h(t) = -16t^2 + 64t, where t is time in seconds after launch. Use the graph of this function to answer the questions. Estimate the time when the fireball is at its maximum height.
A. 2.3 seconds

B. 2 seconds

C. 0 seconds

D. 4 seconds
Mathematics
1 answer:
Zigmanuir [339]3 years ago
3 0

Answer: C or 2 seconds.

Step-by-step explanation:

To find the vertex in a standard form equation: (-b/2a,f(-b/2a))

plug it in: -64/2*-32 = 2

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List all the factors of 16 ​
Ronch [10]

Answer:

1,2,4,8,16

Step-by-step explanation:

prime factorization: 2x2x2x2 =16

4 0
2 years ago
g A two-tailed test is one where: Select one: a. results in only one direction can lead to rejection of the null hypothesis b. n
e-lub [12.9K]

Answer:

c. results in either of two directions can lead to rejection of the null hypothesis.

Step-by-step explanation:

A two tailed test is performed when we want to test if there is statistically significant difference from the null state. That means that if the statistic value is significantly higher or significantly lower, we will reject the null hypothesis. Both tails have rejection areas.

8 0
3 years ago
The endpoints of EF<br> are E(1,3) and F(-2,8).<br> Find EF.
Phantasy [73]

Answer:

EF = \sqrt{34} ≈ 5.83

Step-by-step explanation:

Calculate EF using the distance formula

d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with (x₁, y₁ ) = E(1, 3) and (x₂, y₂ ) = F(- 2, 8)

EF = \sqrt{(-2-1)^2+(8-3)^2}

    = \sqrt{(-3)^2+5^2}

    = \sqrt{9+25}

    = \sqrt{34} ≈ 5.83 ( to 2 dec. places )

8 0
2 years ago
Craig’s school has 4 lessons in the morning lessons 1 starts at 8:35 each lesson is 60 minutes long there is a break between les
jasenka [17]

Answer:

12:50 PM.

Step-by-step explanation:

We have been given that Craig’s school has 4 lessons in the morning and lesson 1 starts at 8:35. Each lesson is 60 minutes long. There is a break of 15 minutes between lesson 2 and 3.

We can see that lesson 1 will end at 9:35 AM and second lesson will end at 10:35 AM.

We have been also given that there is a break for 15 minutes between lesson 2 and 3. So third lesson will start at 10:50 AM as lunch break will end at 10:50 AM.

Third lesson will end 60 minutes after 10:50 AM that is 11:50 AM and fourth lesson will end 60 minutes after 11:50 AM that is 12:50 PM.

Therefore, 4th lesson will end at 12:50 PM.    

6 0
2 years ago
Find the surface area of the cylinder to the nearest tenth of a square unit. Use 3.14 for pi :))) thank you !!
Leni [432]

Answer:

390.8 ft2 I think

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
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