Find the area of the triangles and smal ler square and add them together ; and find the area of the complete square and set them equal to each other (these are known truths)
triangle: l×w /2
square: s^2
There are 4 triangles so
4 (1/2ab)+c^2= (a+b)(a+b)
simplify
2ab+c^2= a^2+2ab+b^2
-2ab both sides
c^2=a^2+b^2
tada!! it's proven :)
Answer:

Step-by-step explanation:
step 1
Find the slope of the perpendicular line
we know that
If two lines are perpendicular, then their slopes are opposite reciprocal
(the product of their slopes is equal to -1)
In this problem
we have

The equation of the given line is 
so
the slope of the perpendicular line to the given line is

step 2
Find the equation of the line in point slope form

we have


substitute

Convert to slope intercept form

Distribute right side



Answer:
Option C is correct.
Step-by-step explanation:
A direct variation function is
y/x = k
i.e. we can say that the ratio of y and x is equal to a constant value k.
We will check for each Option given.
Option A
7/2 = 7/2
8/3 = 8/3
9/4 = 9/4
10/5 = 2
11/6 = 11/6
Option D is incorrect as y/x ≠ k as ratio of y/x for each value of table doesn't equal to constant
Option B
-3/2 = -3/2
-5/4 = -5/4
-6/6 = -1
-7/8 = -7/8
-8/10 = -4/5
Option B is incorrect as y/x ≠ k as ratio of y/x for each value of table doesn't equal to constant
Option C
10/-5 = -2
8/-4 = -2
6/-3 = -2
4/-2 = -2
2/-1 = -2
Option C is correct as y/x = k as ratio of y/x for each value in table c is equal to constant value -2
Option D
-3/-2 = 3/2
-3/1 = -3
-3/0 = 0
-3/1 = -3
-3/2 = -3/2
Option D is incorrect as y/x ≠ k as ratio of y/x for each value of table doesn't equal to constant .
SO, Option C is correct.
Answer:
<u>Option C</u>
Step-by-step explanation:
Given 0.5≤ x ≤ 0.7
According to the range of x, we will check which option is true
Let x = 0.6
A. 
If x = 0.6
∴0.6/3 > √0.6 ⇒ 0.2 > 0.77 ⇒ <u>Wrong inequality </u>
B. x³ > 1/x
If x = 0.6
∴ 0.6³ > 1/0.6 ⇒ 0.216 > 1.667 ⇒ <u>Wrong inequality </u>
<u></u>
C. √x > x³
If x = 0.6
∴ √0.6 > 0.6³ ⇒ 0.77 > 0.216 ⇒ <u>True inequality </u>
D. (x/3) > (1/x)
If x = 0.6
∴ 0.6/3 > 1/0.6 ⇒ 0.2 > 1.667 ⇒<u> Wrong inequality </u>
<u>So, The true inequality is option C</u>