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2 years ago

Figure ABCD is transformed to figure A prime B prime C prime D prime, as shown below:

1 answer:

3 0

The figure ABCD reflected over the y-axis followed by a translation to the left by 2 unit to form figure A'B'C'D'

<h3>What is a transformation?</h3>

Transformation is the movement of a point from its initial location to a new location. Types of transformation are <em>translation, rotation, reflection and dilation.</em>

Dilation is the increase or decrease in the size of a figure.

The figure ABCD reflected over the y-axis followed by a translation to the left by 2 unit to form figure A'B'C'D'

Find out more on transformation at: brainly.com/question/4289712

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How would I find the integral of <img src="https://tex.z-dn.net/?f=%5Cint%5Cfrac%7Btdt%7D%7Bt%5E4%2B2%7D" id="TexFormula1" title

kotegsom [21]

Let $t=\sqrt y$ , so that $t^2=y$ , $t^4=y^2$ , and $\mathrm dt=\dfrac{\mathrm dy}{2\sqrt y}$ . Then

$\displaystyle\int\frac t{t^4+2}\,\mathrm dt=\int\frac{\sqrt y}{2\sqrt y(y^2+2)}\,\mathrm dy=\frac12\int\frac{\mathrm dy}{y^2+2}$

Now let $y=\sqrt2\tan z$ , so that $\mathrm dy=\sqrt2\sec^2z\,\mathrm dz$ . Then

$\displaystyle\frac12\int\frac{\mathrm dy}{y^2+2}=\frac12\int\frac{\sqrt2\sec^2z}{(\sqrt2\tan z)+2}\,\mathrm dz=\frac{\sqrt2}4\int\frac{\sec^2z}{\tan^2z+1}\,\mathrm dz=\frac1{2\sqrt2}\int\mathrm dz=\dfrac1{2\sqrt2}z+C$

Transform back to $y$ to get

$\dfrac1{2\sqrt2}\arctan\left(\dfrac y{\sqrt2}\right)+C$

and again to get back a result in terms of $t$ .

$\dfrac1{2\sqrt2}\arctan\left(\dfrac{t^2}{\sqrt2}\right)+C$

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3 years ago

Find the length of the missing side

balu736 [363]

Answer:

x = 11.1

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3 years ago

F f(x) = 3x + 2 and g(x) = x2 + 1, which expression is equivalent to (f circle g) (x)?

seraphim [82]

f°g mean apply g(x) and then use result of g(x) as "x" in f(x)

so as g(x) = x² +1 and f(x) = 3x+2

so if we call g(x) X we have

f( X) = 3 X +2

now we replace " X" for it's value

f(X) = 3 ( x² +1) +2

f(X) = 3x² +3 +2

f(X) = 3x² +5

so f°g = 3x² +5

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2 years ago

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sveta [45]

True the whole statement is true

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3 years ago

Given the formula, solve for the indicated variable. <br> F=9/5c + 32 for c

SVEN [57.7K]

F = $\frac{9}{5}$ c + 32 Subtract 32 from both sides
F - 32 = $\frac{9}{5}$ c Mutliply both sides by <span> $\frac{5}{9}$ to cancel out the fraction
</span> $\frac{5}{9}$ F - 17 $\frac{7}{9}$ = c Switch the sides to make it easier to read
c = $\frac{5}{9}$ F - 17 <span> $\frac{7}{9}$ </span>

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3 years ago