The cost of a ravens hat is $24 . The store is selling it $30 What is the markup rate of the hat

Today’s cafeteria specials are a turkey sandwich and a pepperoni pizza. During 1st lunch, the cafeteria sold 70 turkey sandwiche

sveticcg [70]

Answer:

$4 and $3

Step-by-step explanation:

First, write out the equations as 70x + 29y = 367 and 70x + 45y = 415. Solve by using the elimination method by subtracting 70x from 70x. 45y minus 29y is equal to 16y. 415 minus 367 is 48. Divide 48 by 16, to get y is equal to get y is equal to three. Y represents pepperoni pizzas, so a pepperoni pizza costs $3. Plug a 3 into any equation for y and solve for x. 29 times 3 is 87. 367 minus 87 is 280. 280 divided by 70 is equal to 4, so x is equal to 4.

3 0

3 years ago

I dont get this simple math 3 2/1÷ 4/3=

mel-nik [20]

uhm I can't help with that... sorry

7 0

3 years ago

If u(x)=-2x^2+3 and v(x)=1/x what is the range of (u*v)(x) **the picture should help

nasty-shy [4]

We have that
$u(x)=-2 x^{2} +3 \\ \\ v(x)= \frac{1}{x}$
$u(v(x))=u( \frac{1}{x})=-2( \frac{1}{x} )^{2} +3 \\ u( \frac{1}{x})= \frac{(3 x^{2} -2)}{ x^{2} }$

using a graph tool
see the attached figure

The horizontal asymptote of this function is at y=3.
So,
the range of this function is from (−∞,3)

5 0

3 years ago

Read 2 more answers

Consider an espresso stand with a single barista. Customers arrive at the stand at the rate of 28 per hour according to a Poisso

Snowcat [4.5K]

Answer:

The average number of customers in the system is 3.2

Step-by-step explanation:

The average number of customes in the system is given by:

$L = \frac{\lambda^{2}}{\mu(\mu - \lambda)}$

In which

$\lambda$ is the number of arirvals per time period

$\mu$ is the average number of people being served per period.

The number of arrivals is modeled by the Poisson distribution, while the service time is modeled by the exponential distribution.

Customers arrive at the stand at the rate of 28 per hour

This means that $\lambda = 28$

Service times are exponentially distributed with a service rate of 35 customers per hour.

This means that $\mu = 35$ . So

The average number of customers in the system (i.e., waiting and being served) is

$L = \frac{\lambda^{2}}{\mu(\mu - \lambda)}$

$L = \frac{28^{2}}{35(35 - 28)} = 3.2$

The average number of customers in the system is 3.2

4 0

3 years ago

BRIANLIST ANSWER pls help i meant to put science

melisa1 [442]

Answer:

I'd say Yev's description is best because it's the most specific to what it actually is in terms of science, while everyone else's descriptions are more like examples of different types and stages of energy, and where it could be found.

Hope this makes sense to ya :)

4 0

3 years ago