Answer:
is standard equation of hyperbola with vertices at (0, ±9) and foci at (0, ±11).
Step-by-step explanation:
We have given the vertices at (0, ±9) and foci at (0, ±11).
Let (0,±a) = (0,±9) and (0,±c) = (0,±11)
The standard equation of parabola is:

From statement, a = 9
c² = a²+b²
(11)² = (9)²+b²
121-81 = b²
40 = b²
Putting the value of a² and b² in standard equation of parabola, we have
which is the answer.
The given expression written in the simplest rational exponent form is 
<h3>Writing an Expression in Exponent form</h3>
From the question, we are to write the given expression in exponent form
The given expression is
![\sqrt{x} \times \sqrt[4]{x}](https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D%20%20%5Ctimes%20%5Csqrt%5B4%5D%7Bx%7D)
In exponent form,

and
![\sqrt[4]{x} = x^{\frac{1}{4} }](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bx%7D%20%3D%20x%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D)
Thus,
becomes

Applying the multiplication law of indices, we get

= 
Hence, the given expression written in the simplest rational exponent form is 
Learn more on Writing an expression in exponent form here: brainly.com/question/4421494
#SPJ1
Answer:
Proof with Statement and Reason is below.
Step-by-step explanation:
Given:
In The Figure
BF ⊥ AC,CE ⊥ AB
To Prove:
Δ ACE ≅ Δ ABF
Proof:
In Δ ACE and Δ ABF
STATEMENT REASONS
1. BF ⊥ AC,CE ⊥ AB Given
2. m∠ BFA = 90°,m∠ CEA = 90° { Perpendicular Lines BF ⊥ AC,CE ⊥ AB }
3. AE = FA Given
4. m∠ A = m∠ A {Reflexive property}
5. Δ ACE ≅ Δ ABF By AAS Congruence Postulate
Using the binomial distribution, it is found that there is a 0.7447 = 74.47% probability that fewer than 7 of them show up.
<h3>What is the binomial distribution formula?</h3>
The formula is:


The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem, the values of the parameters are given as follows:
p = 0.7, n = 8.
The probability that fewer than 7 of them show up is given by:
[tec]P(X < 7) = 1 - P(X \geq 7)[/tex]
In which:

Then:



Then:

[tec]P(X < 7) = 1 - P(X \geq 7) = 1 - 0.2553 = 0.7447[/tex]
0.7447 = 74.47% probability that fewer than 7 of them show up.
More can be learned about the binomial distribution at brainly.com/question/24863377
#SPJ1