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irga5000 [103]
3 years ago
6

Cards with the numbers 1 through 40 are placed in a box and throughly shuffled. What is the probability of randomly selecting a

card with a number less than 10 or a multiple of 15? a) 3/10; b) 11/40; c) 1/20; d) 7/400
Mathematics
1 answer:
Alecsey [184]3 years ago
5 0
There are 9 numbers less than 10.  1,2,3,4,5,6,7,8,9
And there are 2 multiples of 15.  15,30
There are 11 of the 40 cards that are either less than 10 or multiples of 15,  so the answer is B
You might be interested in
Find an equation in standard form for the hyperbola with vertices at (0, ±9) and foci at (0, ±11)
Katen [24]

Answer:

\frac{y^{2} }{81} -\frac{x^{2} }{40} }=1 is standard equation of hyperbola with vertices at (0, ±9) and foci at (0, ±11).

Step-by-step explanation:

We have given the vertices at (0, ±9) and foci at (0, ±11).

Let (0,±a)  = (0,±9) and (0,±c)  = (0,±11)

The standard equation of parabola is:

\frac{y^{2} }{a^{2} } -\frac{x^{2} }{b^{2} }=1

From statement, a  = 9

c² = a²+b²

(11)²  = (9)²+b²

121-81  = b²

40  = b²

Putting the value of a² and b² in standard equation of parabola, we have

\frac{y^{2} }{81} -\frac{x^{2} }{40} }=1 which is the answer.

3 0
3 years ago
Rewrite in simplest rational exponent form <img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D%20%2A%20%5Csqrt%5B4%5D%7Bx%7D" id="T
Shkiper50 [21]

The given expression written in the simplest rational exponent form is x^{\frac{3}{4} }

<h3>Writing an Expression in Exponent form</h3>

From the question, we are to write the given expression in exponent form

The given expression is

\sqrt{x}  \times \sqrt[4]{x}

In exponent form,

\sqrt{x}  = x^{\frac{1}{2} }

and

\sqrt[4]{x} = x^{\frac{1}{4} }

Thus,  \sqrt{x}  \times \sqrt[4]{x} becomes

x^{\frac{1}{2} } \times x^{\frac{1}{4} }

Applying the multiplication law of indices, we get

x^{\frac{1}{2} + \frac{1}{4} }

= x^{\frac{3}{4} }

Hence, the given expression written in the simplest rational exponent form is x^{\frac{3}{4} }

Learn more on Writing an expression in exponent form here: brainly.com/question/4421494

#SPJ1

5 0
1 year ago
PLEASE ANSWER WILL MARK BRAINLIEST
zepelin [54]

Answer:

Proof with Statement and Reason is below.

Step-by-step explanation:

Given:

In The Figure

BF ⊥ AC,CE ⊥ AB

To Prove:

Δ ACE ≅ Δ ABF

Proof:

In Δ ACE and Δ ABF

STATEMENT REASONS

1. BF ⊥ AC,CE ⊥ AB Given

2. m∠ BFA = 90°,m∠ CEA = 90° { Perpendicular Lines BF ⊥ AC,CE ⊥ AB }

3. AE = FA                 Given

4. m∠ A = m∠ A       {Reflexive property}

5. Δ ACE ≅ Δ ABF   By AAS Congruence Postulate

8 0
3 years ago
Helpppppppppp meeeeeeeeee pllzzzzzzzzz
Fantom [35]

Using the binomial distribution, it is found that there is a 0.7447 = 74.47% probability that fewer than 7 of them show up.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem, the values of the parameters are given as follows:

p = 0.7, n = 8.

The probability that fewer than 7 of them show up is given by:

[tec]P(X < 7) = 1 - P(X \geq 7)[/tex]

In which:

P(X \geq 7) = P(X = 7) + P(X = 8)

Then:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 7) = C_{8,7}.(0.7)^{7}.(0.3)^{1} = 0.1977

P(X = 8) = C_{8,8}.(0.7)^{8}.(0.3)^{0} = 0.0576

Then:

P(X \geq 7) = P(X = 7) + P(X = 8) = 0.1977 + 0.0576 = 0.2553

[tec]P(X < 7) = 1 - P(X \geq 7) = 1 - 0.2553 = 0.7447[/tex]

0.7447 = 74.47% probability that fewer than 7 of them show up.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

8 0
2 years ago
2/9 of my number is 4. what is my number?<br><br> Be the brainy one ny answerinng the question OK?
bogdanovich [222]
18 should be your number
4 0
3 years ago
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