Answer:
.09
Step-by-step explanation:
I just did it in my brain
It is parallel due to the fact that it is the exact same number with one being positive and one being negative.
Answer:
Step-by-step explanation:
If COP and TOD are vertical angles, then they are equal to each other because vertical angles are equal.
m COP = m TOD
Given
COP = 11x - 17
TOD = 9x + 11.
Substitute:
11x-17 = 9x+11
11x-9x = 11+17
2x = 28
x = 28/2
x = 14
Get <COD
<COP = 11(14)-17
<COP = 154-17
<COP = 137
<COD = 180-<COP
<COD = 180-137
<COD = 43°
Similarly:
<POT = 180 - <TOD
<POT = 180 - [9(14)+11]
<POT = 180 - 137
<POT = 43°
Step-by-step explanation:
Let's take the RHS,
we've,
<h3>(<u>Cosa</u><u>/</u><u>2</u><u> </u><u>-</u><u> </u><u>sina</u><u>/</u><u>2</u><u>)</u></h3><h3>(<u>Cosa/</u><u>2</u><u> </u><u>+</u><u> </u><u>sina</u><u>/</u><u>2</u><u>)</u></h3>
Let's Rationalise the Denominator.
we get,
<h3>(<u>Cosa/</u><u>2</u><u> </u><u>-</u><u> </u><u>sina</u><u>/</u><u>2</u><u>)</u><u>^</u><u>2</u></h3><h3><u>(</u><u>cosa</u><u>/</u><u>2</u><u>)</u><u>^</u><u>2</u><u> </u><u>-</u><u> </u><u>(</u><u>sina</u><u>/</u><u>2</u><u>)</u><u>^</u><u>2</u></h3>
The numerator is in form of (a-b)^2 and the denominator is in form of a^2-b^2. Now,
By formula,
<h3>(<u>Cosa/</u><u>2</u><u>)</u><u>^</u><u>2</u><u> </u><u>-2cosa</u><u>/</u><u>2</u><u>.</u><u>s</u><u>i</u><u>n</u><u>a</u><u>/</u><u>2</u><u> </u><u>+</u><u> </u><u>(</u><u>sina</u><u>/</u><u>2</u><u>)</u><u>^</u><u>2</u> </h3><h3> cosa</h3>
Here I substituted Cosa in place of (Cosa/2)^2 - (sina/2)^2 because it's the formula of cosa in sub multiple angle form.
<h3>In the numerator, </h3>
(sina/2)^2 + (Cosa/2)^2 =1.........( by formula)
so we have,
<h3><u>1</u><u> </u><u>-</u><u> </u><u>2</u><u>s</u><u>i</u><u>n</u><u>a</u><u>/</u><u>2</u><u>.</u><u>c</u><u>o</u><u>s</u><u>a</u><u>/</u><u>2</u></h3><h3>Cosa</h3>
<h3 /><h3 /><h3><u>1</u><u> </u><u>-</u><u> </u><u>sina</u> {because 2sina/2.cosa/2=sina)</h3><h3>Cosa</h3>
LHS proved.
Thank You.
<span>distributive property
</span><span>D.(0.5 ⋅ 0.5) + (0.5 ⋅ 0.3) + (0.5 ⋅ 0.2) = 0.5 ⋅ (0.5 + 0.3 + 0.2) </span><span>
</span>