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ololo11 [35]
4 years ago
15

Write a quadratic function in standard form with zeros 9 and -4

Mathematics
1 answer:
OverLord2011 [107]4 years ago
8 0
if\ x_1\ and\ x_2\ zeros,\ then\ quadratic\ function\:\\\\f(x)=a(x-x_1)(x-x_2)\\\\\\9;\ -4-zeros,\ then:\\\\f(x)=a(x-9)(x+4)=a(x^2+4x-9x-36)=a(x^2-5x-36)\\\\\\if\ a=1\ then\ f(x)=x^2-5x-36
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Answer:

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Step-by-step explanation:

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Answer:

a₁₅ = 71

Step-by-step explanation:

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a_{n} = a₁ + (n - 1)d

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Answer:

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Step-by-step explanation:

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3 years ago
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Tju [1.3M]

Answer:

y = \frac{z^2 - x}{2}

Step-by-step explanation:

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\sqrt{x + 2y} = z

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Solve for y (make y the subject of the formula)

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\sqrt{x + 2y} = z

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Divide both sides by 2

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Step-by-step explanation:

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