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ololo11 [35]
3 years ago
15

Write a quadratic function in standard form with zeros 9 and -4

Mathematics
1 answer:
OverLord2011 [107]3 years ago
8 0
if\ x_1\ and\ x_2\ zeros,\ then\ quadratic\ function\:\\\\f(x)=a(x-x_1)(x-x_2)\\\\\\9;\ -4-zeros,\ then:\\\\f(x)=a(x-9)(x+4)=a(x^2+4x-9x-36)=a(x^2-5x-36)\\\\\\if\ a=1\ then\ f(x)=x^2-5x-36
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Answer:

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Step-by-step explanation:

Formula = K=\frac{y}{x}

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Where k is the constant of proportionality.

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We substitute these known values in the equation,

y = kx

1.5 = k5

Dividing both sides of the equation by 5 to find the value for k, we have

1.5/5= k0.3/5

Therefore,

K = 0.3

Having found the value of k,

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