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2 years ago

How do i write 1.67 in words

2 answers:

5 0

Many people would say "one point six seven" or "one dot six seven".

But technically, it's "one and sixty-seven hundredths".

Oksana_A [137]2 years ago

5 0

Its One Hundred and Sixty-Seven the decimal is always gonna be called and GOT IT NOW !

You might be interested in

How do you round 2.8497 × 10^3 and 349.69 to 3 significant figures?

Kobotan [32]

Your answer for rounding 2.8497 x 10^3 is correct: 2.85 x 10^3.

350.0 is not correct because it has 4 sig figs. The proper rounding would be simply 350. with not additional zeros.

6 0

2 years ago

A national grocery store chain wants to test the difference in the average weight of turkeys sold in Detroit and the average wei

Arte-miy333 [17]

Answer:

Calculated value t = 1.3622 < 2.081 at 0.05 level of significance with 42 degrees of freedom

The null hypothesis is accepted .

Assume the population variances are approximately the same

Step-by-step explanation:

Explanation:-

Given data a random sample of 20 turkeys sold at the chain's stores in Detroit yielded a sample mean of 17.53 pounds, with a sample standard deviation of 3.2 pounds

The first sample size 'n₁'= 20

mean of the first sample 'x₁⁻'= 17.53 pounds

standard deviation of first sample S₁ = 3.2 pounds

Given data a random sample of 24 turkeys sold at the chain's stores in Charlotte yielded a sample mean of 14.89 pounds, with a sample standard deviation of 2.7 pounds

The second sample size n₂ = 24

mean of the second sample "x₂⁻"= 14.89 pounds

standard deviation of second sample S₂ = 2.7 pounds

Null hypothesis:-H₀: The Population Variance are approximately same

Alternatively hypothesis: H₁:The Population Variance are approximately same

Level of significance ∝ =0.05

Degrees of freedom ν = n₁ +n₂ -2 =20+24-2 = 42

Test statistic :-

$t = \frac{x^{-} _{1} - x_{2} }{\sqrt{S^2(\frac{1}{n_{1} } }+\frac{1}{n_{2} } }$

where $S^{2} = \frac{n_{1} S_{1} ^{2}+n_{2}S_{2} ^{2} }{n_{1} +n_{2} -2}$

$S^{2} = \frac{20X(3.2)^2+24X(2.7)^2}{20+24-2}$

substitute values and we get S² = 40.988

$t= \frac{17.53-14.89 }{\sqrt{40.988(\frac{1}{20} }+\frac{1}{24} )}$

t = 1.3622

Calculated value t = 1.3622

Tabulated value 't' = 2.081

Calculated value t = 1.3622 < 2.081 at 0.05 level of significance with 42 degrees of freedom

Conclusion:-

The null hypothesis is accepted

Assume the population variances are approximately the same.

6 0

2 years ago

benjamin has a mask collection. he keeps 144 masks on the wall which is 48% of his collection. what is the total number of mask

Mekhanik [1.2K]

Answer:

Banjamin has 300 masks total.

6 0

2 years ago

Read 2 more answers

6 units to the right of 0

kondor19780726 [428]

Im sure this means add because on a number line when you move to the right its adding. And since the amount of units were moving up by is 6 we would add 0+6 which equals 6.

5 0

2 years ago

If t follows a t7 distribution, find t0 such that (a) p(|t | < t0) = .9 and (b) p(t > t0) = .05.

Thepotemich [5.8K]

Answer:

a) $P(-t_o < t_7$

Using the symmetrical property we can write this like this:

$1-2P(t_7$

We can solve for the probability like this:

$2P(t_7$

$P(t_7$

And we can find the value using the following excel code: "=T.INV(0.05,7)"

So on this case the answer would be $t_o =\pm 1.895$

b) For this case we can use the complement rule and we got:

$1-P(t_7$

We can solve for the probability and we got:

$P(t_7$

And we can use the following excel code to find the value"=T.INV(0.95;7)"

And the answer would be $t_o = 1.895$

Step-by-step explanation:

Previous concepts

The t distribution (Student’s t-distribution) is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".

The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.

The degrees of freedom represent "the number of independent observations in a set of data. For example if we estimate a mean score from a single sample, the number of independent observations would be equal to the sample size minus one."

Solution to the problem

For this case we know that $t \sim t(df=7)$

And we want to find:

Part a

$P(|t|$

We can rewrite the expression using properties for the absolute value like this:

$P(-t_o < t_7$

Using the symmetrical property we can write this like this:

$1-2P(t_7$

We can solve for the probability like this:

$2P(t_7$

$P(t_7$

And we can find the value using the following excel code: "=T.INV(0.05,7)"

So on this case the answer would be $t_o =\pm 1.895$

Part b

$P(t>t_o) =0.05$

For this case we can use the complement rule and we got:

$1-P(t_7$

We can solve for the probability and we got:

$P(t_7$

And we can use the following excel code to find the value"=T.INV(0.95;7)"

And the answer would be $t_o = 1.895$

5 0

2 years ago