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scZoUnD [109]
2 years ago
8

Part II: Describe the pattern of the following sequence. (2 points)

Mathematics
1 answer:
Marizza181 [45]2 years ago
7 0

1 subract 6

2 add 8

3 add 11

4 subract 5

5 add 10

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PLEASE HELP!! (Look at photo)
Mila [183]

Answer:

C

10 x (p+2) = 30

10 x 2 = 20 30 - 20 = 10 10 ÷ 10 = 1

P = 1

10 x (1 + 2) = 30

5 0
3 years ago
Can you help me plz i will give you brainly its
hodyreva [135]
The answer is 3.5 + 1.5x = 12.5. So the answer would be C.
4 0
3 years ago
A local school district requires all fourth graders to complete a 20-minute test containing 200 multiple-choice mathematics prob
Readme [11.4K]

The component of mathematics fluency is most likely the goal of this type of assessment is Rate.

GIven,

A local school district requires all fourth graders to complete a 20-minute test containing 200 multiple-choice mathematics problems.

The component of mathematics fluency is most likely the goal of this type of assessment is Rate.

The school district is assessing the rate because they are seeing how many questions students can answer in a given time frame.

Hence, The component of mathematics fluency is most likely the goal of this type of assessment is Rate.

Learn more about the Component of mathematics here brainly.com/question/24407396

#SPJ4

3 0
2 years ago
Miguel cut 1/4 from a round pie. Mariah cut a piece from the same pie an angle measure of 60 ° . who cut a larger piece
gogolik [260]
There are 360 degrees in a circle. 1/4 * 360 = 90 degrees

90 degrees > 60 degrees meaning Miguel cut the larger piece by 30 degrees
4 0
3 years ago
I need help with my algebra 2. I also want to know how to solve this.
Lisa [10]

Add 1 to both sides:

\sqrt{x+3} = x+1

In cases like this, we have to remember that a root is always positive, so we can square both sides only assuming that

x+1 \geq 0 \iff x \geq -1

Under this assumption, we square both sides and we have

x+3 = (x+1)^2 \iff x+3 = x^2+2x+1 \iff x^2+x-2 = 0

The solutions to this equation are

x = -2,\ x=1

But since we can only accept solutions greater than -1, we discard x=-2 and accept x=1.

In fact, we have

x=-2 \implies \sqrt{-2+3}-1=0\neq -2

and

x=1 \implies \sqrt{4}-1=1

which is the only solution.

4 0
4 years ago
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