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2 years ago

1. The perimeter of the square is f(x) = 4x, where x is the side of the square. Find the domain of the function.

2 answers:

6 0

If the perimeter of the square is 4x then the domain of the function will be set of rational numbers and the domain of the function y=3x+8(3-x) is set of real numbers.

Given The perimeter of the square is f(x)=4x and the function is y=3x+8(3-x)

We will first solve the first part in which we have been given that the perimeter of the square is 4x and we have to find the domain of the function.

First option is set of rational numbers which is right for the function.

Second option is set of whole numbers which is not right as whole number involves 0 also and the side of the square is not equal to 0.

Third option is set of integers which is not right as integers involve negative number also and side of square cannot be negative.

Hence the domain is set of rational numbers.

Now we will solve the second part of the question

f(x)=3x+8(3-x)

we have not told about the range of the function so we can put any value in the function and most appropriate option will be set of real numbers as real number involve positive , negative and decimal values also.

Learn more about perimeter here brainly.com/question/19819849

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FinnZ [79.3K]2 years ago

3 0

Question 1

B. Set of whole numbers

Eliminate A and C because negative integers are in those sets.

Question 2

A. Set of real numbers

The equation represents a line, which has a domain of all real numbers.

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3 years ago

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3 years ago

Which of the following is the equation of

Neporo4naja [7]

Answer:

a) Option A is correct.

b) Option C is correct.

Step-by-step explanation:

a) Which of the following is the equation of the line passing through the points (1, 1) and (-3,5)?

We will use the equation

(y-y₁)=m(x-x₁)

m= (y₂-y₁)/(x₂-x₁)

m= (5-1)/(-3-1)

m= 4/-4

m= -1

Consider point (1,1) and Putting value of m

(y-y₁)=m(x-x₁)

(y-1)=1(x-1)

y-1=x-1

y=x-1+1

y=x

So, Option A is correct.

b) Which of the following is the equation of a line with a slope of 0 passing through (2,5)?

The formula used is:

y= mx+b

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5=0(2)+b

=> b = 5

So, equation is:

y = mx+b

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3 years ago

Perform the indicated operation and express the result as a simplified complex number. I need help with 35

skelet666 [1.2K]

Given:-

$\frac{3+4i}{2-i}$

To find:-

The simplified form.

At first we take conjucate and multiply below and above.

The conjucate is,

$2+i$

So now we multiply. we get,

$\frac{3+4i}{2-i}\times\frac{2+i}{2+i}$

Now we simplify. so we get,

$\frac{3+4i}{2-i}\times\frac{2+i}{2+i}=\frac{6+3i+8i+4(i)^2}{2^2-i^2}$

We know the value of,

$i^2=-1$

Substituting the value -1. we get,

$\begin{gathered} \frac{6+3i+8i+4(i)^2}{2^2-i^2}=\frac{6+3i+8i+4(-1)_{}^{}}{2^2-(-1)^{}} \\ \text{ =}\frac{6-4+11i}{2+1} \\ \text{ =}\frac{2+11i}{3} \end{gathered}$

So now we split the term to bring it into the form a+ib. so we get,

$\frac{2+11i}{3}=\frac{2}{3}+i\frac{11}{3}$

So the required solution is,

$\frac{2}{3}+i\frac{11}{3}$

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1 year ago