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2 years ago

Write 4 fractions that are equivalent to 6/8.

Mathematics

2 answers:

Talja [164]2 years ago

5 0

Answer:

6/8 is an equivalent fraction of 3/4.

We can find some other equivalent fractions by multiplying the numerator and the denominator of the given fraction by the same number. Thus, the equivalent fractions of 3/4 are 6/8, 9/12, 12/16, and 15/20.

GuDViN [60]2 years ago

4 0

Answer:

below

Step-by-step explanation:

6/8 = 3/4, 9/12, 12/16 and 15/20

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The coordinates on a map for City A are (57, 11) and those for City B are (121, 79). Note that coordinates represent miles. Find

Juliette [100K]

Answer:

93 miles

Step-by-step explanation:

Use the distance formula:

d = $\sqrt{(x2 - x1)^2 + (y2 - y1)^2}$

Plug in the values:

d = $\sqrt{(121 - 57)^2 + (79 - 11)^2}$

d = $\sqrt{4096 + 4624}$

d = $\sqrt{8720}$

d = 93.4

= 93 miles

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4 years ago

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Given the figure below, find the values of x and z .

eimsori [14]

Z and 96 are vertical angles so they equal each other. The other angle makes a straight line with the 96 degree angle so subtract from 180 to find the measure of that angle is 84. Set the expression equal to 84 and solve.

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3 years ago

I Need Help!!<br><br><br> Identify each congruence transformation that maps ABC to DEF

timama [110]

Answer:

A and F

Step-by-step explanation:

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3 years ago

Two lighthouses are located 75 miles from one another on a north-south line. If a boat is spotted S 40o E from the northern ligh

yuradex [85]

Answer:

The northern lighthouse is approximately $24.4\; \rm mi$ closer to the boat than the southern lighthouse.

Step-by-step explanation:

Refer to the diagram attached. Denote the northern lighthouse as $\rm N$ , the southern lighthouse as $\rm S$ , and the boat as $\rm B$ . These three points would form a triangle.

It is given that two of the angles of this triangle measure $40^{\circ}$ (northern lighthouse, $\angle {\rm N}$ ) and $21^{\circ}$ (southern lighthouse $\angle {\rm S}$ ), respectively. The three angles of any triangle add up to $180^{\circ}$ . Therefore, the third angle of this triangle would measure $180^{\circ} - (40^{\circ} + 21^{\circ}) = 119^{\circ}$ (boat $\angle {\rm B}$ .)

It is also given that the length between the two lighthouses (length of $\rm NS$ ) is $75\; \rm mi$ .

By the law of sine, the length of a side in a given triangle would be proportional to the angle opposite to that side. For example, in the triangle in this question, $\angle {\rm B}$ is opposite to side $\rm NS$ , whereas $\angle {\rm S}$ is opposite to side ${\rm NB}$ . Therefore:

$\begin{aligned} \frac{\text{length of NS}}{\sin(\angle {\rm B})} = \frac{\text{length of NB}}{\sin(\angle {\rm S})} \end{aligned}$ .

Substitute in the known measurements:

$\begin{aligned} \frac{75\; \rm mi}{\sin(119^{\circ})} = \frac{\text{length of NB}}{\sin(21^{\circ})} \end{aligned}$ .

Rearrange and solve for the length of $\rm NB$ :

$\begin{aligned} & \text{length of NB} \\ =\; & (75\; \rm mi) \times \frac{\sin(21^{\circ})}{\sin(119^{\circ})} \\ \approx\; & 30.73\; \rm mi\end{aligned}$ .

(Round to at least one more decimal places than the values in the choices.)

Likewise, with $\angle {\rm N}$ is opposite to side ${\rm SB}$ , the following would also hold:

$\begin{aligned} \frac{\text{length of NS}}{\sin(\angle {\rm B})} = \frac{\text{length of SB}}{\sin(\angle {\rm N})} \end{aligned}$ .

$\begin{aligned} \frac{75\; \rm mi}{\sin(119^{\circ})} = \frac{\text{length of SB}}{\sin(40^{\circ})} \end{aligned}$ .

$\begin{aligned} & \text{length of SB} \\ =\; & (75\; \rm mi) \times \frac{\sin(40^{\circ})}{\sin(119^{\circ})} \\ \approx\; & 55.12\; \rm mi\end{aligned}$ .

In other words, the distance between the northern lighthouse and the boat is approximately $30.73\; \rm mi$ , whereas the distance between the southern lighthouse and the boat is approximately $55.12\; \rm mi$ . Hence the conclusion.