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3 years ago

The digits of a certain three-digit number are consecutive odd numbers. If the sum of the digits is 15, find the number.

2 answers:

6 0

Let the digits of the 3 digit number be $x-2,x,x+2$ . where $x$ is an integer greater than 1. It is given that the sum of the 3 digits is 15. Hence,

$x-2+x+x+2=15\\ 3x=15\\ x=5$

Thus the digits are $3,5,7$ .

Therefore, the number is $357$ .

We assume that the digits of the number is increasing from the 100th place.

scoray [572]3 years ago

3 0

The answer is 5 because it is consecutive 3 times and it is an odd number

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Find dy/dx by implicit differentiation for x + 2y = xy.

Stella [2.4K]

Ok to find dy/dx of x+2y=xy we take derivative of both sides with respect to x

1+2dy/dx = x*dy/dx +y*dx/dx
1+ 2dy/dx = x*dy/dx + y* 1
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2y’ + 1 = xy’ + y

2y’ + 1 - xy’ = y

2y’ -xy’ = y - 1

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3 years ago

The manager of a bank recorded the amount of time each customer spent waiting in line during peak business hours one Monday. The

zavuch27 [327]

The standard deviation of the frequency distribution is 5.54

<h3>How to determine standard deviation?</h3>

The table of values is given as:

x f(x)

0-3 13

4-7 13

8-11 10

12-15 11

16-19 0

20-23 3

Rewrite the table by calculating the class midpoints:

x f(x)

1.5 13

5.5 13

9.5 10

13.5 11

17.5 0

21.5 3

Start by calculating the mean using:

$\bar x = \frac{\sum fx}{\sum f}$

This gives

$\bar x = \frac{1.5 * 13 + 5.5 * 13 + 9.5 * 10 + 13.5 * 11 + 17.5 * 0 + 21.5 * 3}{13 + 13 + 10 + 11 + 0 +3}$

Evaluate

$\bar x = 7.98$

The standard deviation is then calculated as:

$\sigma = \sqrt{\frac{\sum f(x - \bar x)^2}{\sum f }}$

So, we have:

$\sigma= \sqrt{\frac{13 * (1.5 - 7.98)^2 + 13 * (5.5 - 7.98)^2 + (9.5 - 7.98)^2 * 10 + (13.5 - 7.98)^2 * 11 + (17.5 - 7.98)^2 * 0 + (21.5 - 7.98)^2 * 3}{13 + 13 + 10 + 11 + 0 +3}}$