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gtnhenbr [62]
4 years ago
14

The digits of a certain three-digit number are consecutive odd numbers. If the sum of the digits is 15, find the number.

Mathematics
2 answers:
Oksi-84 [34.3K]4 years ago
6 0

Let the digits of the 3 digit number be x-2,x,x+2. where x is an integer greater than 1. It is given that the sum of the 3 digits is 15. Hence,

x-2+x+x+2=15\\ 3x=15\\ x=5

Thus the digits are 3,5,7.

Therefore, the number is 357.

We assume that the digits of the number is increasing from the 100th place.

scoray [572]4 years ago
3 0
The answer is 5 because it is consecutive 3 times and it is an odd number
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Vikentia [17]

Answer:

1: 130

2: 70

Step-by-step explanation:

Supplementary angles add up to equal 180

So to find the measure of the missing angles, we subtract the measure of the known angles from 180

For #1

∠B = 180 - 50

180 - 50 = 130

Hence ∠B = 130

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8 0
3 years ago
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3 years ago
Suppose an=3an-1 -5an-2 -4an-3. and a4= -7, a5=-36, a6=-85 , find a1 , a2, a3​
maria [59]

Answer:

        a_1=4\\\\a_2=0\\\\a_3=3

Explanation:

The equation is:

      a_n=3a_{n-1}-5a_{n-2}-4a_{n-3}

and

      a_4=-7, a_5=-36, a_6=-85

<u>1. Subsittute n = 6 into the equation:</u>

      a_6=3a_{5}-5a_{4}-4a_{3}

      Now subsititute the known values:

       -85=3(-36)-5(-7)-4a_{3}

      You can solve for a_3

      -85=-108+35-4a_{3}\\\\4a_3=12\\\\a_3=12/4\\\\a_3=3

<u />

<u>2. Substitute n = 5 into the equation:</u>

    a_5=3a_{4}-5a_{3}-4a_{2}

     Substitute the known values and solve for a_2

        -36=3(-7)-5(3)-4a_{2}\\\\4a_2=-21-15+36=0\\\\a_2=0

<u>3. Substitute n = 4 into the equation, subsitute the known values and solve for </u>a_1<u />

       a_4=3a_{3}-5a_{2}-4a_{1}

        -7=3(3)-5(0)-4a_{1}\\\\4a_1=9+7=16\\\\a_1=4

7 0
3 years ago
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