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3 years ago

PLEASE HELP ME PLEASE LOOK AT THE PICTURE I NEED AN ANSWER ASAP

Mathematics

1 answer:

Anvisha [2.4K]3 years ago

5 0

Answer:

1st one is 2. 2nd one is 5. 3rd one is less than. 4th one is, is smaller

Step-by-step explanation:

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PLSSSS HELLPPPPP!!!

eimsori [14]

Answer: B, D, and F

Step-by-step explanation:

Hi, so for this question, the phone bill is in an equation. Before doing this problem, make sure to understand what the 2 and 56 mean. The problem says that c is the monthly charge, and m is the number of minutes. This means that 2 is the number of dollars required to pay when you use the phone for one minute. So 2 dollars per minute. The 56 is basically the fee that is just charged for using the phone bill. Meaning that even if you don't use the phone at all, you will still need to pay 56 dollars.

By understanding those info, it should be easier to answer.

For A, it is not correct. if you look, although 2*4 is 8 dollars, but you need to add 56 for the monthly bill. (I think when they say 'your bill' they mean the monthly bill).

For B, it is correct. Like I said before, the 56 dollars is there no matter how long you use the phone.

For C, it is not correct. This isn't hard to understand since if B is correct, C is probably not, and vise versa. And the 56 dollars is missing.

For D, it is correct. As I said before, the 2 represents the amount of dollars for one minute.

For E, it is not correct. (Contradicts the previous answer and each minute costs 2 dollars).

For F, it is correct. When you use 2 minutes, the equation is 2*2+56 which is 60 dollars.

Hopefully this helps!

3 0

2 years ago

Read 2 more answers

Which numbers are necessary to solve this problem?

Bad White [126]

Hello there.

<span>Which numbers are necessary to solve this problem?

Brian goes to the gym 3 times a week. He exercises for 45 minutes each visit. Fifteen of those minutes are spent on weights and the rest are spent on the treadmill.

How much time does Brian spend on the treadmill in 4 weeks?

Answer: </span><span>3 times a week, 45 minutes, 15 minutes, 4 weeks
</span>

5 0

3 years ago

Read 2 more answers

What is the value of the discriminators 3x^2-4x+2=0

ohaa [14]

Answer:

x =(4-√40)/6=(2-√ 10 )/3= -0.387

x =(4+√40)/6=(2+√ 10 )/3= 1.721

Step-by-step explanation: Hope this helped!!!

plz give me brainliest!! thxxx

3 0

2 years ago

Listed below are prices in dollars for one night at different hotels in a certain region. Find the range, variance, and standar

Artyom0805 [142]

Answer:

Range = 115$

Standard Deviation = 43.76$

Variance = 1915.142$

Option A) The measures of variation are not very useful because when searching for a room, low prices, location, and good accommodations are more important than the amount of variation in the area.

Step-by-step explanation:

We are given the data for prices in dollars for one night at different hotels in a certain region.

234, 160, 119, 131, 218, 207, 146, 141

Range:

Sorted data: 119, 131, 141, 146, 160, 207, 218, 234

$\text{Range} = 234-119 = 115\$$

Standard Deviation:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{1356}{8} = 169.5$

Sum of squares of differences = 4160.25 + 90.25 + 2550.25 + 1482.25 + 2352.25 + 1406.25 + 552.25 + 812.25 = 13406

$\sigma = \sqrt{\dfrac{13406}{7}} = 43.76\$$

Variance =

$\sigma^2 = 1915.142\$$

Measure of variance for someone searching for room:

Option A) The measures of variation are not very useful because when searching for a room, low prices, location, and good accommodations are more important than the amount of variation in the area.

5 0

3 years ago

1 What is 20% of 60?

Contact [7]

Answer:

Step-by-step explanation:

%20 is 1/5

60/5=12

12*5=60

3 0

3 years ago

Read 2 more answers

PLEASE HELP ME PLEASE LOOK AT THE PICTURE I NEED AN ANSWER ASAP​

PLEASE HELP ME PLEASE LOOK AT THE PICTURE I NEED AN ANSWER ASAP