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dmitriy555 [2]
2 years ago
12

Which of the following is a list that follows this pattern with its numbers: prime, prime, prime, composite, prime, prime 1, 5,

7, 9, 11, 13 1, 2, 5, 7, 9, 15 2, 4, 6, 8, 10, 12 11, 9, 3, 2, 5, 4, 8
Mathematics
1 answer:
Pani-rosa [81]2 years ago
7 0

The correct answer is option A which is the pattern {prime, prime, prime, composite, prime, prime} is followed by 1, 5, 7, 9, 11, 13.

<h3>What are prime and composite numbers?</h3>

Prime numbers:-

The prime number is defined as the number which is divided by 1 and itself.

Composite numbers:-

The number is defined as the composite number when the number is divided by 1 itself and any other numbers also.

From the given options we need to choose the pattern of the series { prime, prime, prime, composite, prime, prime } so we can see that in option A correct pattern is followed.

Pattern { 1, 5, 7, 9, 11, 13 }

1   → prime

5  → prime

7  → prime

9  → composite

11  → prime

13 → prime

Therefore the correct answer is option A which is the pattern {prime, prime, prime, composite, prime, prime} is followed by 1, 5, 7, 9, 11, 13.

To know more about prime and composite numbers follow

brainly.com/question/375267

#SPJ1

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Answer:

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0.75*12.8 or 12.8 *3/4 is the answer.

12.8*0.75 = 9.6

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weqwewe [10]

Answer:

∠BKM= ∠ABK

Therefore AB ║KM (∵ ∠BKM= ∠ABK  and lies between AB and KM and BK is the transversal line)

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Step-by-step explanation:

Given: BK is an angle bisector of Δ ABC. and line KM intersect BC such that, BM = MK

TO prove: KM ║AB

Now, As given in figure 1,

In Δ ABC, ∠ABK = ∠KBC (∵ BK is angle bisector)

Now in Δ BMK, ∠MBK = ∠BKM (∵ BM = MK and angles opposite to equal sides of a triangle are equal.)

Now ∵ ∠MBK = ∠BKM

and  ∠ABK = ∠KBM

∴ ∠BKM= ∠ABK

Therefore AB ║KM (∵ ∠BKM= ∠ABK and BK is the transversal line)

Hence proved.  

8 0
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Answer:

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Step-by-step explanation:

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<u>This is divisible by 11 by default as the sum of the digits in odd placed is same as sum of the number in even places (remember the divisibility rule by 11):</u>

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Now, in order to be divisible by 99, the number must be divisible by 11 and 9.

According to divisibility rule by 9 the sum of all digits must be divisible by 9. <u>You can see In our case we need to have (the minimum):</u>

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<u>The smallest number we could get is when x is minimum, y is minimum, so:</u>

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<u>The number we get is:</u>

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<u>Proof:</u>

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