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Jobisdone [24]
2 years ago
12

How to get more brancells?

Mathematics
1 answer:
Greeley [361]2 years ago
4 0

Answer:

Read books, watch documentaries, exercise, anything that benefits your body and mind

Step-by-step explanation:

You might be interested in
XZ = 15 and the perimeter of XWZ is 50. What is the length of WZ?
Rom4ik [11]

Answer:

  17.5

Step-by-step explanation:

The perimeter is the sum of the side lengths:

  perimeter = XZ +WZ +WX

The figure shows us WX = WZ, so we can rewrite the formula as ...

  perimeter = XZ +2·WZ

Filling in the given values, this becomes ...

  50 = 15 + 2·WZ

  35 = 2·WZ

  35/2 = WZ = 17.5

The length of WZ is 17.5 units.

6 0
3 years ago
Number 17 plsss helppp
Tju [1.3M]

Answer:

its b communative property of multiplication

Step-by-step explanation:

3 0
3 years ago
Find the area of a circle that has a radius of 14 feet. Round your answer to the nearest hundredth.
Mice21 [21]
The formula for area of a circle is 
A = π·r²

You are given the radius.
r = 14 feet

Now all you have to do is plug that in and solve.
A = π·14²
A = π·196
A = 615.44

Your answer is 615.44 feet.
3 0
4 years ago
The expression m divided by 4 is the distance each person runs in a relay race that is m miles how far does each person run in a
alexira [117]

Answer: <em>Each person runs 3 miles</em>

Step-by-step explanation:

The race is 12 miles long, so you would substitute it for m.

This would make your equation 12/4, which is equal to 3

5 0
3 years ago
4. [5 pts] Describe how and why the formula for permutations differs from the formula for combinations.
ivann1987 [24]

Answer:

They are different because of the order in the permutation matters. In combination, the order doesn't matter. In other words in a permutation 123 and 132 are different but in a combination are the same group (they have the same digits 1,2, and 3).

Step-by-step explanation:

The formula of the permutation is P(n,r)=\frac{n!}{(n-r)!}, when you are performing a permutation you pick r objects from a total of n, for the first pick you can choose from n, but for the second you have n-1, and this continues to your  pick number r in which you will choose from n-r+1, and the total of permutation is the multiplicación of this number of choices for each pick, like this:

n(n-1)(n-2)...(n-r+1)

If n!=n(n-1)(n-2)...(n-r+1)(n-r)(n-r-1)...(1) and (n-r)!=(n-r)(n-r-1)(n-r-2)...(1)

\frac{n!}{(n-r)!}=\frac{n(n-1)(n-2)...(n-r+1)(n-r)(n-r-1)...(1)}{(n-r)(n-r-1)(n-r-2)...(1)}

The factor equals above and under cancel each other.

\frac{n!}{(n-r)!}=\frac{n(n-1)(n-2)...(n-r+1)(n-r)(n-r-1)...(1)}{(n-r)(n-r-1)(n-r-2)...(1)}\\\frac{n!}{(n-r)!}=n(n-1)(n-2)...(n-r+1)

In combination, the order of the element isn't important, so from the total of permutation you have to eliminate the ones with the same objects with different order and counting just once each group, when choosing r objects the total of permutation for a single group of r objects is: r(r-1)(r-2)...(1)=r!. If you divide the total of permutations of n taking r by r! you get the combinations (where the order is not important). The formula of the combination is C(n,r)=\frac{n!}{r!(n-r)!}.

4 0
4 years ago
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