A.3n+4+3n+4+4n
=3n+3n+4n+4+4
=10n+8
B.11n+4+n-12
=11n+n+4-12
=12n-8
C.6(6n-2)
=36n-12
D.4(3n-2)
=12n-8
E.4n+22-12+8n
=4n+8n+22-12
=12n+10
so,B and D are the expressions that are equivalent to 12n-8.
8x + 7y = 39
4x - 14y = -68
(multiply each term in second equation by -2)
8x + 7y = 39
-8x + 28y = 136
(add both equations)
35y = 175
(divide both sides by 35)
y = 5
(substitute value of y in one of the equations)
8x + 7(5) = 39
8x + 35 = 39
8x = 4
x = 1/2
(x, y) = (1/2, 5)
Answer:
50
Step-by-step explanation:
For this question you would follow the BIDMAS rule - (Brackets, Indices, Division, Multiplication, Addition, Subtraction.)
The first thing in this question you need to solve it (9 + 8)
we do this because, when we follow BIDMAS, the first rule is brackets
so, 9 + 8 = 17
The second step is to multiply, as this rule is second,
so, 17 x 2 = 34
Our final step is to solve the last bit, which is 6 x 14
and we know that 6 x 14 = 84
So now that we have 84 and 34, we need to subtract the two numbers as shown,
84 - 34 = 50
And this is how you get the answer 50
i hope this has helped you, please comment if you did not understand it and i will explain it in another way : )
