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1 year ago

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Which of the following best describes the ordered pairs listed below? (-3, 4), (2, -6), (7, -16), (9, -20) A. function only B. b

oth a relation and a function C. neither a relation nor a function D. relation only

1 answer:

Andrei [34K]1 year ago

7 0

C neither a relation or a function

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I need help with this one plis quickly !!!

shutvik [7]

Answer:

3

Step-by-step explanation:

Hard to see but pretty sure thats it

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2 years ago

If you have 21 cats and give 2 away how much will you have

nexus9112 [7]

Answer:

19

Step-by-step explanation:

21 - 2 is 19

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3 years ago

Read 2 more answers

A researcher plans to conduct a significance test at the 0.01 significance level. She designs her study to have a power of 0.90

Rasek [7]

Answer: 0.10

Step-by-step explanation: The type 2 error is committed when the alternative hypothesis is rejected when it should have been accepted causing the researcher to accept the null hypothesis which is false.

Power is the probability of avoiding a type 2 error. That is ;

Power = 1 - P(type 2 error)

Given that power = 0.90 ; P(type 2 error) = probability of committing a type 2 error.

P(type 2 error)' = 1 - P(type 2 error) = Probability of not committing or avoiding a type 2 error

0.90 = 1 - P(type 2 error)

P(type 2 error) = 1 - 0.90

P(type 2 error) = 0.10

6 0

2 years ago

If r=20.5 and s=34.2 find S Round to the nearest tenth

astraxan [27]

Answer: option d

Step-by-step explanation:

Remember the identity:

$tan\alpha=\frac{opposite}{adjacent}$

The inverse of the tangent function is arctangent. You need to use this to calculate the angle "S":

$\alpha =arctan(\frac{opposite}{adjacent})$

Knowing that: you need to find the measure of the angle "S" , $r=20.5$ (which is the adjacent side) and $s=34.2$ (which is the opposite side), you can sustitute values into $\alpha =arctan(\frac{opposite}{adjacent})$

Then, you get that the measure of "S" rounded to the nearest tenth is:

$S=arctan(\frac{34.2}{20.5})\\\\S=59.1\°$

7 0

3 years ago

Read 2 more answers

Simplify the expression 6C2

iVinArrow [24]

Answer:

$^6C_2=15$

Step-by-step explanation:

Recall the formula:

$^nC_r=\frac{n!}{(n-r)!r!}$

We apply this formula to simplify $^6C_2$

This implies that:

$^6C_2=\frac{6!}{(6-2)!2!}$

$^6C_2=\frac{6!}{4!2!}$

$^6C_2=\frac{6\times5\times4!}{4!\times 2\times1}$

This simplifies to

$^6C_2=\frac{6\times5}{2\times1}$

$^6C_2=\frac{3\times5}{1\times1}=15$

8 0

3 years ago