Ask question

Ask question

All categories

2 years ago

15

It took Sheldon 17 5/6 minutes to walk to Raj's house. The bus ride home took Sheldon 4 5/8 minutes. How many more minutes did i

t take Sheldon to walk than to take the bus?

1 answer:

MA_775_DIABLO [31]2 years ago

4 0

Answer:

it will take her $13\frac{5}{24}$ minutes more to walk down to Raj's House

Step-by-step explanation:

It took Sheldon $17 \frac{5}{6}$ minutes to walk to Raj's house

It also took Sheldon $4\frac{5}{8}$ minutes to use the bus.

To get the time difference between the two transport mechanisms, we subtract their different time durations.

This will be

$17\frac{5}{6} - 4\frac{5}{8}=317/24$

We can convert this to Mixed fractions as shown $13\frac{5}{24}$ minutes.

Therefore, it will take her $13\frac{5}{24}$ minutes more to walk down to Raj's House

You might be interested in

Just answer number 7 and 8

melamori03 [73]

We are given the equation:
F = 2.25+0.2(m-1)
where:
F is the fare
m is the number of miles.

In question 7, we are given that the fare (F) is equal to $6.05 and we need to get the number of miles. To do so, we will simply substitute with the fare in the given equation and solve for the number of miles (m) as follows:
F = 2.25 + 0.2(m-1)
6.05 = 2.25 + 0.2(m-1)
6.05-2.25 = 0.2(m-1)
3.8 = 0.2(m-1)
3.8/0.2 = m-1
19 = m-1
m = 19+1
m = 20 miles

Number 8 is exactly the same, but we will substitute F=7.65 and again solve for m

4 0

2 years ago

Svetllana [295]

Answer:

1) $2w + 2(3w) \leq 112$

2) $850w > 300w + 7500$

3) The greatest age that Sue could be is 7.

4) The smaller of the two integers is 92.

5) Don needs to earn at least 244 points in the fourth game.

Step-by-step explanation:

1) An rectangle has 2 dimensions: width(w) and length(l)

The perimeter P is:

$P = 2w + 2l$

The problem states that the length of a rectangle is three times its width. So l = 3w and:

$P = 2w + 2(3w)$

The perimeter of the rectangle is at most 112 cm. It means that the perimeter can be 112, so the equal sign enters the inequality. So

$2w + 2(3w) \leq 112$

2)

The problem states that he earns $850 per week in sales. His earnings is modeled by the following equation:

$E = 850*w$ , in which w is the number of weeks.

The problem also states that he spent $7500 to obtain his merchandise, and it costs him $300 per week for general expenses. So his expenses can be modeled by the following equation

$C = 300*w + 7500$ , in which w is also the number of weeks.

He will make a profit when his earnings are bigger than his expenses, so: When they are equal, there is no profit, so the equal sign does not enter the inequality.

$E > C$

$850w > 300w + 7500$

3)

I am going to call Jenny's age x and Sue's age y.

The problem states that Jenny is eight years older than twice her cousin Sue’s age. So

$x = 8 + 2y$ .

The sum of their ages is less than 32, so:

$x + y < 32$

$8 + 2y + y < 32$

$3y < 24$

$y < \frac{24}{3}$

$y < 8$

Sue's age has to be less than 8, so the greatest age that Sue could be is 7.

4)

The sum of two consecutive integers is at least 185.

There are two integers with sum of 185, so:

$x + y = 185$

They are consecutive so:

$x = y + 1$

Replacing in the sum equation:

$y + 1 + y = 185$

$2y = 184$

$y = \frac{184}{2}$

$y = 92$

The smaller of the two integers is 92.

5)

The average is the sum of all the scores divided by the number of games. So:

$225 = \frac{192 + 214 + 250 + x}{4}$

$656 + x = 900$

$x = 900 - 656$

$x = 244$

Don needs to earn at least 244 points in the fourth game.

8 0

3 years ago

A submarine is located 25 meters below sea level it goes up 7 meters then goes down 38 meters wrote plan integer to represent th

uranmaximum [27]

The question is somewhat confusing but assuming you mean where the submarine is after moving up 7 meters then down 38 meters the submarine would now be located 56 meters below sea level

7 0

2 years ago

Consider a population consisting of the number of teachers per college at small 2-year colleges. Suppose that the number of teac

agasfer [191]

Answer:

a) $\frac{8}{9}$ =0.89

b) 0.8413

Step-by-step explanation:

we know that

$P(║ x -\mu║ \leq k\sigma) \geq 1 -\frac{1}{k^2}$

$so, \mu = 150, \sigma = 20$

$k = \frac{210 - 150}{20} =\frac{150 - 90}{20} = 3$

$P(║ x -150 ║ \leq 3\times 20) \geq 1 -\frac{1}{3^2} = \frac{8}{9}$

x - N(150, 20^2)

$P(X \leq 170) = 0.8413447$

check

$P norm = \frac{170 - 150}{20}= 0.8413447$

8 0

3 years ago

The roots of a quadratic equation ax2+bx+c=0 are 1+i 5 and 1−i 5 . Find possible values of a, b and c.

Anarel [89]

Answer:

Step-by-step explanation:

If the roots are 1 + 5i and 1 - 5i, then you need the factors that result from those roots. They are (x - 1 + 5i) and (x - 1 - 5i). Now what you do with those is FOIL them out. Doing that gives you the following:

$x^2-x+5ix-x+1-5i-5ix+5i-25i^2$ (what a mess, huh?)

The good thing is that several of those terms cancel each other out. +5ix cancels out the -5ix; -5i cancels out the 5i; and the 2 -x terms combine to -2x. That leaves you with:

$x^2-2x-25i^2$

Obviously you're in the section in math that deals with complex (imaginary) numbers so you should know that i-squared is equal to -1. Making that replacement:

$x^2-2x+25$

a = 1, b = -2, c = 25

6 0

3 years ago

Read 2 more answers