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1 year ago

Which two statements are true for reversible reactions that reach dynamic equilibrium?

Physics

1 answer:

Snowcat [4.5K]1 year ago

5 0

The correct statement for reversible reactions that reach dynamic equilibrium is option C "the rates of the forward reaction is equal to the rate of backward reactions at equilibrium."

<h3>What is dynamic equilibrium?</h3>

The dynamic equilibrium is defined as a state of a particular system wherein the reversible reaction takes place and ceases modifying the ratio of reactants as well as products.

The chemical reaction is a method for creating novel chemicals with unique features.

Therefore, the correct answer will be an option (C).

To know more about reaction and dynamic equilibrium

brainly.com/question/2363073

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Gravity is a force between any two objects with mass wht doesn’t a person feel a gravitational force between them herself and an

kipiarov [429]

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Hope its helps u!

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3 years ago

. An object has a position given by ~r(t) = [3.0 m − (4.00 m/s)t]ˆı + [6.0 m − (8.00 m/s2 )t 2 ]ˆ , where all quantities are in

kupik [55]

Answer:

Explanation:

The position is $r(t) = [3.0 \text{ m} - (4.00 \text{ m/s})t]\hat{i} + [6.0 \text{m} - (8.00 \text{ m/s}^2 )t^2 ]\hat{j}$ .

The velocity is the first time-derivative of <em>r(t).</em>

<em /> $v(t) = \dfrac{d}{dt}r(t) = -4.00\,\hat{i} -16t\,\hat{j}$ <em />

The acceleration is the first time-derivative of the velocity.

$a(t) = \dfrac{d}{dt} v(t) = -16\hat{j}$

Since <em>a(t)</em> does not have the variable <em>t</em>, it is constant. Hence, at any time,

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2 years ago

A penny is dropped from the top of a tower. It hits the ground below after 2.5 s. How tall was the tower?

pychu [463]

Answer:

C. 30.6m

Explanation:

To find the height of the tower, we are to use Newtons law of motion to solve this problem. Since the penny is falling from the top of the tower, it is acted by the acceleration due to gravity. The formula to be used is:

$H=ut+\frac{1}{2}gt^2$

Where H is the height of the tower, t is the time taken to hit the ground, u is the initial velocity and g is the acceleration due to gravity.

Given that, t = 2.5 s, g =9.8 m/s², u = 0 m/s (at the top of tower)

$H=ut+\frac{1}{2}gt^2\\\\H=0(2.5)+ \frac{1}{2}(9.8)(2.5)^2\\\\H=30.6\ m$

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3 years ago

A 1,680 kg satellite is in a circular orbit around Earth with a tangential speed of 6,578 m/s. What is the height of the satelli

balu736 [363]

Answer:

Recall that Earth’s radius is 6.38 × 106 m and Earth’s mass is 5.97 × 1024 kg.

Explanation:

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3 years ago

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GalinKa [24]

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3 years ago