All categories

3 years ago

how do the retinas of the eyes of night hunting animals differ from the retinas of animals that hunt during the day time

2 answers:

5 0

Hello,

Night-hunting animals have more rod cells than day-hunting animals. This is most likely because night-hunting animals have to be able to see better than day-hunting animals.

maksim [4K]3 years ago

4 0

Night hunting animals have more rod cells in their retinas which allows them to see better in the dark.

You might be interested in

Why is it important to use constants in an experiment?

Firlakuza [10]

In order for the results to be valid, the dependent variable can only be affected by the independent variable, so somethings need to be kept constant. The things that need to be kept constant are called controlled variables.

5 0

3 years ago

g Suppose that you charge a 3 F capacitor in a circuit containing eight 3.0 V batteries, so the final potential difference acros

Vladimir79 [104]

The complex, highly technical formula for capacitors is

Q = C V

Charge = (capacitance) (voltage)

Charge = (3 F) (24 V)

Charge = 72 Coulombs

The positive plate of the capacitor is missing 72 coulombs worth of electrons. They were sucked into positive terminal of the battery stack.

The negative plate of the capacitor has 72 coulombs worth of extra electrons. They came from the negative terminal of the battery stack.

You should be aware that this is a humongous amount of charge ! An average lightning bolt, where electrons flow between a cloud and the ground for a short time, is estimated to transfer around 15 coulombs of charge !

The scenario in the question involves a "supercapacitor". 3 F is is no ordinary component ... One distributor I checked lists one of these that's able to stand 24 volts on it, but that product costs $35 apiece, you have to order at least 100 of them at a time, and they take 2 weeks to get.

Also, IF you can charge this animal to 24 volts, it will hold 864J of energy. You'd probably have a hard time accomplishing this task with a bag of leftover AA batteries.

7 0

3 years ago

As blood passes through the capillary bed in an organ, the capillaries join to form venules (small veins). If the blood speed in

Semenov [28]

Answer:

$A_2 = 2.5\ cm^2$

Explanation:

given,

velocity factor = 4

Cross-sectional area of venules(A₁) = 10 cm²

cross sectional area of capillaries(A_2) = ?

continuity equation = Q = AV

now,

$\dfrac{A_1}{A_2} = \dfrac{V_2}{V_1}$

$\dfrac{10}{A_2} =4$

$\dfrac{10}{4} =A_2$

$A_2 = 2.5\ cm^2$

hence, the area of capillaries is equal to 2.5 cm₂

4 0

3 years ago

A 23 g bullet traveling at 230 m/s penetrates a 2.0 kg block of wood and emerges cleanly at 170 m/s. If the block is stationary

Ann [662]

The distance traveled by the wood after the bullet emerges is 0.16 m.

The given parameters;

mass of the bullet, m = 23 g = 0.023 g
speed of the bullet, u = 230 m/s
mass of the wood, m = 2 kg
final speed of the bullet, v = 170 m/s
coefficient of friction, μ = 0.15

The final velocity of the wood after the bullet hits is calculated as follows;

$m_1u_1 + m_2 u_2 = m_1v_1 + m_2v_2\\\\0.023(230) + 2(0) = 0.023(170) + 2v_2\\\\5.29 = 3.91 + 2v_2\\\\2v_2 = 1.38\\\\v_2 = \frac{1.38}{2} = 0.69 \ m/s$