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timama [110]
3 years ago
13

3. The function of the _______ is to convert the up-and-down motion of the piston into rotary motion that can be used to power t

he vehicle.

Physics
2 answers:
DENIUS [597]3 years ago
5 0
The function of the crankshaft is to convert the up-and-dwon motion of the piston into rotary motion that can be used to power the vehicle.

I attache an image of a crankshaft.

The pistons are connected to the crank pins ans when the pistons move up an down the crankshaft rotate, and so the recoprating movement of the pistons is converted into rotary motion.

Dmitriy789 [7]3 years ago
5 0

Answer:

crankshaft

Explanation:

it is the CRANKSHAFT because this is what goes around

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As a prank, your friends have kidnapped you in your sleep, and transported you out onto the ice covering a local pond. When you
Ilia_Sergeevich [38]

Answer:

Explained

Explanation:

You should throw your boot in the direction away from the closest shore so that the reaction force is towards the closest shore.

8 0
3 years ago
In which of the basic regions of the galaxy is the sun located?
AlladinOne [14]

galactic disk


The galactic disk is a thinned, leveled out distribution of stars which includes the typical to the largest and brightest. The Sun is in the Milky Way and lies amongst the majority of the stars where it bulges.


8 0
4 years ago
A 5 kg ball is suspended on one cable. Calculate the tension in the cable
ludmilkaskok [199]

Answer:

49N

Explanation:

F=ma

We know the mass is 5kg, and since the ball is suspended on one cable, the acceleration is g, 9.8m/s^2

F=5kg*9.8m/s^2

 = 49N

Hope this helps!

7 0
3 years ago
A person of mass 70 kg stands at the center of a rotating merry-go-round platform of radius 2.9 m and moment of inertia 900 kg⋅m
Cloud [144]

Explanation:

It is given that,

Mass of person, m = 70 kg

Radius of merry go round, r = 2.9 m

The moment of inertia, I_1=900\ kg.m^2

Initial angular velocity of the platform, \omega=0.95\ rad/s

Part A,

Let \omega_2 is the angular velocity when the person reaches the edge. We need to find it. It can be calculated using the conservation of angular momentum as :

I_1\omega_1=I_2\omega_2

Here, I_2=I_1+mr^2

I_1\omega_1=(I_1+mr^2)\omega_2

900\times 0.95=(900+70\times (2.9)^2)\omega_2

Solving the above equation, we get the value as :

\omega_2=0.574\ rad/s

Part B,

The initial rotational kinetic energy is given by :

k_i=\dfrac{1}{2}I_1\omega_1^2

k_i=\dfrac{1}{2}\times 900\times (0.95)^2

k_i=406.12\ rad/s

The final rotational kinetic energy is given by :

k_f=\dfrac{1}{2}(I_1+mr^2)\omega_1^2

k_f=\dfrac{1}{2}\times (900+70\times (2.9)^2)(0.574)^2

k_f=245.24\ rad/s

Hence, this is the required solution.

5 0
3 years ago
A spaceship from a friendly, extragalactic planet flies toward Earth at 0.203 0.203 times the speed of light and shines a powerf
Serjik [45]

Answer:

567.321nm

Explanation:

See attached handwritten document for more details

7 0
3 years ago
Read 2 more answers
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