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3 years ago

What are 7 elements from the periodic table that are named after objects in outer space

1 answer:

5 0

Helium... from the greek word helios... the sun
selenium... from the greek word selene... the moon 
palladium.. after the asteroid pallas 
tellurium...from the greek word tellus... the earth 
mercury...after the planet mercury 
cerium... after the asteroid ceres 
uranium...after the planet uranus 
neptunium.. after the planet neptune 
plutonium.. after the planet pluto

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A 06-C charge and a .07-C charge are apart at 3 m apart. What force attracts them?

Andru [333]

Answer:

F = 37.8 × 10^(6) N

Explanation:

The charges are 0.06 C and 0.07 C.

Thus;

Charge 1; q1 = 0.06 C

Charge 2; q2 = 0.07 C

Distance between them; r = 3 m

Formula for the force in between them is;

F = kq1•q2/r²

Where k is a constant = 9 × 10^(9) N.m²/C²

Thus;

F = (9 × 10^(9) × 0.06 × 0.07)/3²

F = 37.8 × 10^(6) N

3 0

2 years ago

Is the force of friction the sum of all the microscopic contact forces between the bottom of the block and the surface?

kotegsom [21]

The force of friction is that force that tends to oppose the motion of the body with the surface in contact... are you clear with it?

6 0

2 years ago

What is the primary force that causes the seafloor to spread and continents to drift?

jekas [21]

The primary force would be Thermal Convection, it pushes it and thus makes continents drift.
-Hope that helps, Nexxmexx :3

5 0

3 years ago

1-Find the gravitational force

butalik [34]

$g = \frac{GMm}{r^2}$

where $G$ is the gravitational constant and is about $6.67 * 10^{-11}$

$g = \frac{6.67 * 10^{-11} * 25 * 0.55}{35^2}$

$g = \frac{6.67 * 10^{-11} * 25 * 0.55}{1225} = 0.000000000000749 N$ :D

5 0

3 years ago

A length of wire is cut into five equal pieces. the five pieces are then connected in parallel, with the resulting resistance be

ycow [4]

The equivalent resistance of resistors connected in parallel is
$\frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2} + ...$
In our problem, we have 5 identical resistor of resistance $R$ , so their equivalent resistance is
$\frac{1}{R_{eq}} = 5 (\frac{1}{R} )$
The problem also says that the equivalent resistance is $R_{eq}= 17 \Omega$ , so we can find the resistance R of each piece of wire:
$R=5 R_{eq} = 5 \cdot 17 \Omega = 85 \Omega$

In the initial wire, it's like the 5 pieces are connected in series, so the equivalent resistance of the wire is just the sum of the resistances of the 5 pieces:
$R_{wire} = 5 R = 5 \cdot 85 \Omega = 425 \Omega$

6 0

3 years ago