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vfiekz [6]
2 years ago
7

What is the centripetal force necessary to keep a 0.4 kg object rotating in a circular path

Physics
1 answer:
ivolga24 [154]2 years ago
7 0

Answer:

ertdhrsg

Explanation:

gesrgsg

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A dart leaves a toy dart gun with initial velocity of 7.76 m/s, regardless of the angle it is fired. What is the maximum horizon
In-s [12.5K]
Vf=vi plus 2 ad
0=7.76 + 2(9.8)d
d=0.395m
4 0
3 years ago
What factors affect the amount of potential and kinetic energy a roller coaster has
Svetlanka [38]

Answer:

As the roller coaster goes higher, more potential energy is increased in the roller coaster. Caused by gravity and the roller coaster's position, the potential energy is stored in the roller coaster. For example, this ball is at the top of a hill, where potential energy is at it's highest. Potential energy can be calculated by Potential Energy=Mass X Acceleration X Height.

Explanation:

3 0
2 years ago
Plz help with these 4
Airida [17]

Answer:

1) The human skeleton performs six major functions: support, movement, protection, production of blood cells, storage of minerals, and endocrine regulation. protection of internal organs

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Explanation:

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5 0
3 years ago
Read 2 more answers
Calculate the percent error of the distanc
Soloha48 [4]

Answer:

5.25%

Explanation:

From the question given above, the following data were obtained:

Accepted value = 238857 miles

Measured value = 226316 miles

Percentage error =.?

Next, we shall determine the absolute error. This can be obtained as follow:

Accepted value = 238857 miles

Measured value = 226316 miles

Absolute Error =?

Absolute Error = |Measured – Accepted|

Absolute Error = |226316 – 238857|

Absolute Error = 12541

Finally, we shall determine the percentage error. This can be obtained as follow:

Accepted value = 238857 miles

Absolute Error = 12541

Percentage error =.?

Percentage error = absolute error / accepted value × 100

Percentage error

= 12541 / 238857 × 100

= 1254100 / 238857

= 5.25%

Therefore, the percentage error is 5.25%.

8 0
3 years ago
Two ropes are attached to a 40-kg object. The first rope applies a force of 25 N and the second, 40 N. If the two ropes are perp
kifflom [539]

Answer:

1.2 m/s^2

Explanation:

I will ignore gravity and friction....and will choose 25 N as UP and 40 N to Left (see diagram)

Resultant force:   R^2 = 25^2 + 40^2        R = sqrt(2225)=47 N

F = ma

F/m = a  

47 N / 40 kg = a = 1.2 m/s^2

8 0
2 years ago
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