What is the centripetal force necessary to keep a 0.4 kg object rotating in a circular path
1 answer:
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At 10 m/s, it will take
(2 m)/(10 m/s) = 0.2 s
to bridge the gap.
_____
However, it will take an additional 0.514 seconds (0.714 s total) for the policeman to land on the building below. The answer depends on the meaning of the question.
(2 m)/(10 m/s) = 0.2 s
to bridge the gap.
_____
However, it will take an additional 0.514 seconds (0.714 s total) for the policeman to land on the building below. The answer depends on the meaning of the question.
Answer:
the mass of the box is 51.98 kg.
Explanation:
Given;
applied horizontal force, F = 450 N
coefficient of friction, μ = 0.795
constant velocity, v = 1.2 m/s
At constant velocity, the acceleration of the object is zero and the net force will be zero.
Therefore, the mass of the box is 51.98 kg.