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yaroslaw [1]
3 years ago
8

Two 8V batteries are set up with four light bulbs in a complex circuit. Light bulb A has a resistance of 4.00 Ω, light bulb B ha

s a resistance of 12.00 Ω, light bulb C has a resistance of 3.00 Ω, and light bulb D has a resistance of 6.00 Ω.
***THREE SIGNIFICANT FIGURES, DO NOT TYPE THE UNIT***

Reff: Ω (Blank #1)

Veff: V (Blank #2)

Ieff: A (Blank #3)



RA: Ω (Blank #4)

VA: V (Blank #5)

IA: A (Blank #6)





RB: Ω (Blank #7)

VB: V (Blank #8)

IB: A (Blank #9)





RC: Ω (Blank #10)

VC: V (Blank #11)

IC: A (Blank #12)





RD: Ω (Blank #13)

VD: V (Blank #14)

ID: A (Blank #15)

Physics
1 answer:
Neko [114]3 years ago
4 0

Answer:

Total resistance : 12.4

Total Current : 0.645

Explanation:

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