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1 year ago

Find the difference or type impossible [9 -1] [4 3] [2 -3] [5 0]

Mathematics

1 answer:

IrinaK [193]1 year ago

3 0

The difference based on the numbers given is -80.

<h3>How to compute the difference?</h3>

The information given illustrates that the difference will be:

= (9 - 1) - (43) - (2 - 3) - 50

= 8 - 43 - (-1) - 50

= 8 - 43 + 1 - 50

= -80

Therefore, the difference or subtraction among the numbers given is -80.

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PLZZZZZZZZZZZZZZZZZ HELP!

zheka24 [161]

Answer:

-8

Step-by-step explanation:

5(x+12)= 20

5x+60= 20

5x= -40

x= -8

3 0

3 years ago

What is the solution to the equation 4x-6=10x-3?

Ulleksa [173]

Answer:

itb would be 60

Step-by-step explanation:

thata my answer

7 0

3 years ago

In one day, the stock price for Warbucks Coffee rose from $50 to $57 per share. By what percent did this stock price rise?

egoroff_w [7]

Answer:

14%

Step-by-step explanation:

1. The formula to find percent change is $\frac{(V_2-V_1)}{|V_1|} * 100$ . Now, all we have to do is plug in the values to their corresponding variable.

2. (Solving)

$\frac{(57-50)}{|50|} * 100$
$\frac{7}{50} *100$

$0.14 * 100$
14%

7 0

3 years ago

A raffle offers one $8000.00 prize, one $4000.00 prize, and five $1600.00 prizes. There are 5000 tickets sold at $5 each. Find t

Harman [31]

Answer:

The expectation is $E(1 )= -\$ 1$

Step-by-step explanation:

From the question we are told that

The first offer is $x_1 = \$ 8000$

The second offer is $x_2 = \$ 4000$

The third offer is $\$ 1600$

The number of tickets is $n = 5000$

The price of each ticket is $p= \$ 5$

Generally expectation is mathematically represented as

$E(x)=\sum x * P(X = x )$

$P(X = x_1 ) = \frac{1}{5000}$ given that they just offer one

$P(X = x_1 ) = 0.0002$

Now

$P(X = x_2 ) = \frac{1}{5000}$ given that they just offer one

$P(X = x_2 ) = 0.0002$

Now

$P(X = x_3 ) = \frac{5}{5000}$ given that they offer five

$P(X = x_3 ) = 0.001$

Hence the expectation is evaluated as

$E(x)=8000 * 0.0002 + 4000 * 0.0002 + 1600 * 0.001$

$E(x)=\$ 4$

Now given that the price for a ticket is $\$ 5$

The actual expectation when price of ticket has been removed is

$E(1 )= 4- 5$

$E(1 )= -\$ 1$

4 0

3 years ago

(a) find parametric equations for the line of intersection of the planes x + y + z = 2 and x + 7y + 7z = 2

nlexa [21]

Direction vector of line of intersection of two planes is the cross product of the normal vectors of the planes, namely
p1: x+y+z=2
p2: x+7y+7z=2

and the corresponding normal vectors are: (equiv. to coeff. of the plane)
n1:<1,1,1>
n2:<1,7,7>

The cross product n1 x n2
vl=
i j l
1 1 1
1 7 7
=<7-7, 1-7, 7-1>
=<0,-6,6>
Simplify by reducing length by a factor of 6
vl=<0,-1,1>

By observing the equations of the two planes, we see that (2,0,0) is a point on the intersection, because this points satisfies both plane equations.

Thus the parametric equation of the line is
L: (2,0,0)+t(0,-1,1)
or
L: x=2, y=-t, z=t

3 0

3 years ago