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xeze [42]
1 year ago
8

Find the difference or type impossible [9 -1] [4 3] [2 -3] [5 0]

Mathematics
1 answer:
IrinaK [193]1 year ago
3 0

The difference based on the numbers given is -80.

<h3>How to compute the difference?</h3>

The information given illustrates that the difference will be:

= (9 - 1) - (43) - (2 - 3) - 50

= 8 - 43 - (-1) - 50

= 8 - 43 + 1 - 50

= -80

Therefore, the difference or subtraction among the numbers given is -80.

Learn more about difference on:

brainly.com/question/148825

#SPJ1

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PLZZZZZZZZZZZZZZZZZ HELP!
zheka24 [161]

Answer:

-8

Step-by-step explanation:

5(x+12)=  20

5x+60= 20  

5x= -40

x= -8

3 0
3 years ago
What is the solution to the equation 4x-6=10x-3?
Ulleksa [173]

Answer:

itb would be 60

Step-by-step explanation:

thata my answer

7 0
2 years ago
In one day, the stock price for Warbucks Coffee rose from $50 to $57 per share. By what percent did this stock price rise?
egoroff_w [7]

Answer:

14%

Step-by-step explanation:

1. The formula to find percent change is \frac{(V_2-V_1)}{|V_1|} * 100. Now, all we have to do is plug in the values to their corresponding variable.

2. (Solving)

  • \frac{(57-50)}{|50|} * 100
  • \frac{7}{50} *100
  • 0.14 * 100
  • 14%
7 0
2 years ago
A raffle offers one $8000.00 prize, one $4000.00 prize, and five $1600.00 prizes. There are 5000 tickets sold at $5 each. Find t
Harman [31]

Answer:

The expectation is  E(1 )= -\$ 1

Step-by-step explanation:

From the question we are told that  

     The first offer is  x_1 =  \$ 8000

     The second offer is  x_2 =  \$ 4000

      The third offer is  \$ 1600

      The number of tickets is  n  =  5000

      The  price of each ticket is  p= \$ 5

Generally expectation is mathematically represented as

             E(x)=\sum  x *  P(X = x )

     P(X =  x_1  ) =  \frac{1}{5000}    given that they just offer one

    P(X =  x_1  ) = 0.0002    

 Now  

     P(X =  x_2  ) =  \frac{1}{5000}    given that they just offer one

     P(X =  x_2  ) = 0.0002    

 Now  

      P(X =  x_3  ) =  \frac{5}{5000}    given that they offer five

       P(X =  x_3  ) = 0.001

Hence the  expectation is evaluated as

       E(x)=8000 *  0.0002 + 4000 *  0.0002 + 1600 * 0.001

      E(x)=\$ 4

Now given that the price for a ticket is  \$ 5

The actual expectation when price of ticket has been removed is

      E(1 )= 4- 5

      E(1 )= -\$ 1

4 0
3 years ago
(a) find parametric equations for the line of intersection of the planes x + y + z = 2 and x + 7y + 7z = 2
nlexa [21]
Direction vector of line of intersection of two planes is the cross product of the normal vectors of the planes, namely
p1: x+y+z=2
p2: x+7y+7z=2

and the corresponding normal vectors are: (equiv. to coeff. of the plane)
n1:<1,1,1>
n2:<1,7,7>

The cross product n1 x n2
vl=
 i  j  l
1 1 1
1 7 7
=<7-7, 1-7, 7-1>
=<0,-6,6>
Simplify by reducing length by a factor of 6
vl=<0,-1,1>

By observing the equations of the two planes, we see that (2,0,0) is a point on the intersection, because this points satisfies both plane equations.

Thus the parametric equation of the line is
L: (2,0,0)+t(0,-1,1)
or
L: x=2, y=-t, z=t

3 0
3 years ago
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