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nika2105 [10]
3 years ago
15

A sweater is marked down from $25 to $18. What is the percent of change

Mathematics
2 answers:
zhenek [66]3 years ago
5 0

Answer:

28 percent off is the answer :)

Step-by-step explanation:

Virty [35]3 years ago
4 0

Answer: -28%

18 - 25 / 25

x 100% = -28%

Step-by-step explanation: A change from 25 to 18 represents a negative change, or decrease of -28.000000000000004%

I hope this is somewhat helpful :)

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2 whole and 2/4 divided by 4 wholes and 1/8
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0.6060606060606

Step-by-step explanation:

6 0
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For each value of u, determine whether it is a solution to 2+9u<-16.
riadik2000 [5.3K]

Answer:

7: no ( the answer will be 65 )

-2 : no ( the answer will be -16 and -16 is not less than -16 instead they're equal)

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Non of them satisfy the condition

Hope this helped

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8 0
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If g(x ) = 3x - 5, then g -1(x )=
NemiM [27]
G(x) = 3x - 5

let g(x) = y

y = 3x - 5

y + 5 = 3x

3x = y + 5

x = (y + 5)/3

From y = g(x),  x = g⁻¹(y) 

<span>x = (y + 5)/3
</span>
 g⁻¹(y)  = <span>(y + 5)/3</span>

 g⁻¹(x)  = <span>(x + 5)/3</span>
6 0
3 years ago
Hiy im in kindergaten and i ned help on my homwwork wat is 5pluss7
inessss [21]

Step-by-step explanation:

5 + 7 = 12 \\

3 0
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Can someone please help me with this question?!? I am so confused and I don't know how to answer it.
lbvjy [14]

9514 1404 393

Answer:

  a. f(0) = 1

  b. DNE (does not exist)

  c. DNE

  d. lim = 3

Step-by-step explanation:

The function exists at a point if it is defined there. The function is defined anywhere on the solid line and at solid dots. It is not defined at open circles. So, the function is defined everywhere except (2, 3), which has an open circle.

The open circle at (0, 4) prevents the function from being doubly-defined at x=0, since it is already defined to be 1 at x=0.

This discussion tells you ...

  f(0) = 1

 f(2) does not exist. There is a "hole" in the function definition there.

__

The function has a limit at a point if approaching from the left and approaching from the right have you approaching that same point.

Consider the point (1, 2). The graph is a solid line through that point. Approaching from values less than x=1, we get to the same point (1, 2) as when we approach from values greater than x=1.

Similarly, consider the point (2, 3). Approaching from values of x less than 2, we get to the same point (2, 3) as when we approach from x-values greater than 2. The limit at x=2 is 3. The only difference from the previous case is that the function is not actually defined to be that value there.

__

Now consider what happens at x=0. When we approach from the left, we approach the point (0, 4). When we approach from the right, we approach the point (0, 1). These are different points. Because they are different coming from the left and from the right, we say "the limit as x→0 does not exist."

__

In summary, ...

  a) f(0) = 1

  b) lim x → 0 does not exist

  c) f(2) does not exist

  d) lim x → 2 = 3

_____

<em>Additional comment</em>

The significance of the function not being defined at a point where the limit exists, (2, 3), is that <em>the function is not continuous there</em>. This kind of discontinuity is called "removable", because we could make the function continuous at x=2 by defining f(2) = 3 (that is, "filling the hole").

6 0
2 years ago
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