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Morgarella [4.7K]
2 years ago
8

The concentration of lead nitrate Pb(NO3)2

Chemistry
1 answer:
Ugo [173]2 years ago
6 0

Answer: The concentration of lead nitrate Pb(NO3)2 in a 0.726 M solution is 0.755 molal.

Explanation:

<u>Given:</u>

The molar mass of Pb(NO3)2 is <u>331.2 g/mol</u>

Assuming 1 litre of solution.  This would equal <u>1202 g</u> of solution

In the one litre of solution, you have 0.726 mol Pb(NO3)2

0.726 mol (331.2 g/mol) = 240.5 g Pb(NO3)2

Mass of water in 1 L of solution = 1202 g - 240.5 g = 961.5 g = 0.9615 kg

Molality = mols of solute / kg of solvent

= 0.726 mol / 0.9615 kg

= 0.755 <em>m</em> Pb(NO3)2

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