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bonufazy [111]
3 years ago
5

The volume of an object is 80.0cm3 and its mass is 253g. Calculate the density of this object using the correct number of signif

icant figures.
Chemistry
1 answer:
jonny [76]3 years ago
6 0
3.1625 i think that's what it is beacuse you have to divide the mass by the volume to get the density
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Which statement describes a chemical property that can be used to distinguish between compound A and compound B?
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Explanation:

(4) A does not burn in air, and B does burn in air is your answer. Flammability is a chemical property while the rest of these are physical properties.

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Which gases help to control the Earth’s temperature?
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carbon dioxide

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If a stack of 1,008 alkali fuel cells in series generates 14,800 W of power, and each cell contributes equally to the power of t
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Each cell contributes power of 14.7 Watts.

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Which set of numbers gives the correct possible values of I for n = 22
Alexandra [31]

Answer:

Hello friends

Explanation:

<h3>For a given principal quantum number for or n, the corresponding angular quantum number or is equivalent to a range between 0 and( n-1)</h3>

<h3>This means that the angular quantum number for a principal quantum number of 2 is equivalent to.</h3>

<h3>1 = 0 - > (n - 1) = 0 - > (2 - 1) = 0 - > 1</h3>

<h3>Hope it's helpfully. </h3>
4 0
3 years ago
Consider the reaction 4HCl(g) + O2(g)2H2O(g) + 2Cl2(g) Using standard thermodynamic data at 298K, calculate the entropy change f
Ulleksa [173]

<u>Answer:</u> The value of \Delta S^o for the surrounding when given amount of HCl gas is reacted is 73.21 J/K

<u>Explanation:</u>

Entropy change is defined as the difference in entropy of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate entropy change is of a reaction is:

\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{(product)}]-\sum [n\times \Delta S^o_{(reactant)}]

For the given chemical reaction:

4HCl(g)+O_2(g)\rightarrow 2H_2O(g)+2Cl_2(g)

The equation for the entropy change of the above reaction is:  

\Delta S^o_{rxn}=[(2\times \Delta S^o_{(Cl_2(g))})+(2\times \Delta S^o_{(H_2O(g))})]-[(4\times \Delta S^o_{(HCl(g))})+(1\times \Delta S^o_{(O_2(g))})]

We are given:

\Delta S^o_{(O_2(g))}=205.14J/K.mol\\\Delta So_{(HCl(g))}=186.91J/K.mol\\\Delta S^o_{(Cl_2(g))}=223.07J/K.mol\\\Delta S^o_{(H_2O(g))}=188.82J/K.mol

Putting values in above equation, we get:

\Delta S^o_{rxn}=[(2\times (223.07))+(2\times (188.82))]-[(4\times (186.91))+(1\times (205.14))]\\\\\Delta S^o_{rxn}=-129J/K

Entropy change of the surrounding = - (Entropy change of the system) = -(-129) J/K = 129 J/K

We are given:

Moles of HCl gas reacted = 2.27 moles

By Stoichiometry of the reaction:

When 4 mole of HCl gas is reacted, the entropy change of the surrounding will be 129 J/K

So, when 2.27 moles of HCl gas is reacted, the entropy change of the surrounding will be = \frac{129}{4}\times 2.27=73.21J/K

Hence, the value of \Delta S^o for the surrounding when given amount of HCl gas is reacted is 73.21 J/K

3 0
3 years ago
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