Answer:
y = 23
x = -4.5
Step-by-step explanation:
Given:
Equation
8x + y = -13 ......eq1
8x + 2y = 10........eq2
Find:
Solution
Computation:
Eq2 - Eq1
y = 23
From eq1
8x + y = -13
8x + 23 = -13
8x = -36
x = -4.5
Answer: Polygon Q's area is 1/4 of Polygon P's area
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Explanation:
Imagine we had a square with side length 8. The area of this square is 8*8 = 64.
Now let's reduce each side of the square by the scale factor 1/2. So each new side is 8*(1/2) = 4. The area of this smaller square is 4*4 = 16.
Comparing the new area (16) to the old one (64), we see that the new area is 16/64 = 1/4 of the old area.
In other words,
new smaller area = (1/4)*(old larger area)
So this is one example to see why (1/2)*(1/2) = 1/4 is the area scale factor based on the linear scale factor of 1/2. In short, (1/2)^2 = 1/4. Whatever the original scale factor is, square it and you'll get the area scale factor.
Answer:
Option D RX=4 units
Step-by-step explanation:
we know that
<em>In the right triangle RTS</em>
The cosine of angle TRS is equal to
cos(TRS)=RT/RS
substitute
cos(TRS)=6/9 -----> equation A
<em>In the right triangle RTX</em>
The cosine of angle TRX is equal to
cos(TRX)=RX/RT
substitute
cos(TRX)=RX/6 -----> equation B
∠TRS=∠TRX -----> is the same angle
Match equation A and equation B
6/9=RX/6
RX=6*6/9=4 units
