Answer:
<u><em>507 x 8 in standard algorithim is equivelant to the answer.</em></u>=
Step-by-step explanation:
5 0 7
× 8
+ 4 0 5 6
= 4 0 5 6
________________________
Therefore:
507 × 8 = 4056
Answer:
i am troll you shall be thou trolled
Step-by-step explanation:
Answer:
Let x be the number of left handed female students and let y be the number of left handed male students.
Then the number of right handed female students will be 5x and the number of right handed male students will be 9y. Since the total number of left handed students is 18 and the total number of right handed students is 122, the following system of equations must be satisfied.
x+y=18 and 5x+9y=122
Solving this system gives x=10 and y=8.
Thus, 50 of the 122 right handed students are female. Therefore, the probability that a right handed student selected at random is female is the fraction 50/122
which to the nearest thousandth is 0.410.
T is average time spend by shoppers in minutes
N average number of shoppers.
Here, shoppers/hour =84.
Hence r=
60
84
T=5
Hence N=rT=
60
84
×5=7
Average number of shoppers waiting at checkout =7
9514 1404 393
Answer:
(b) ... confirm ∠C≅∠E
Step-by-step explanation:
The first step is to read and understand the problem statement. It is asking for a way to prove ΔABC ~ ΔADE by AA similarity. That means you want to show any two of the three ...
For this purpose, lengths of line segments are irrelevant (eliminating the last two answer choices). The fact that ∠A≅∠A is given, so you only need to find an answer choice that will show one of the last two angle congruences.
Obviously, showing ∠B≅∠E (choice A) is not relevant to the problem.
The only answer choice that is relevant to the question is the second one, showing ∠C≅∠E.
Answer:
5
Step-by-step explanation:
let the number written on the board be x.
1st student's number= x +23
2nd student's number= x -1
<em>1</em><em>st</em><em> </em><em>student</em><em>'</em><em>s</em><em> </em><em>number</em><em>=</em><em> </em><em>7</em><em>(</em><em>t</em><em>h</em><em>a</em><em>t</em><em> </em><em>o</em><em>f</em><em> </em><em>the</em><em> </em><em>2nd</em><em> </em><em>student</em><em>)</em><em>,</em>
x +23= 7(x -1)
x +23= 7x -7 <em>(</em><em>expand</em><em>)</em>
7x -x= 23 +7 <em>(</em><em>bring</em><em> </em><em>constant</em><em> </em><em>to</em><em> </em><em>1</em><em> </em><em>side</em><em>)</em>
6x= 30 <em>(</em><em>simplify</em><em>)</em>
x= 30 ÷6 (÷6 on both sides)
x= 5
Thus, the number written on the board is 5.
