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Yanka [14]
3 years ago
7

PLEASE HELP ME!!!!!!!!does anyone know how to do this I am clueless please help

Mathematics
1 answer:
vredina [299]3 years ago
6 0
Maybe this will help! (:
https://youtu.be/1wPJfzStBqE
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How do I find the base of a triangle and the remaining side lengths?
Ann [662]
You look at the triangle...

The sides there are four

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8 0
3 years ago
A rectangle has an area of 19.38 cm2. When both the length and width of the rectangle are increased by 1.50 cm, the area of the
Lostsunrise [7]

Answer: 5.7\ cm

Step-by-step explanation:

Given

Rectangle has an area of 19.38\ cm^2

Suppose rectangle length and width are l and w

If each side is increased by 1.50\ cm

Area becomes A_2=35.28\ cm^2

We can write

\Rightarrow lw=19.38\quad \ldots(i)\\\\\Rightarrow (l+1.5)(w+1.5)=35.28\\\Rightarrow lw+1.5(l+w)+1.5^2=35.28\\\text{use (i) for}\ lw\\\Rightarrow 19.38+1.5(l+w)=35.28-2.25\\\Rightarrow l+w=9.1\quad \ldots(ii)

Substitute the value of width from (ii) in equation (i)

\Rightarrow l(9.1-l)=19.38\\\Rightarrow l^2-9.1l+19.38=0\\\\\Rightarrow l=\dfrac{9.1\pm\sqrt{(-9.1)^2-4(1)(19.38)}}{2\times 1}\\\\\Rightarrow l=\dfrac{9.1\pm\sqrt{5.29}}{2}\\\\\Rightarrow l=\dfrac{9.1\pm2.3}{2}\\\\\Rightarrow l=3.4,\ 5.7

Width corresponding to these lengths

w=5.7,\ 3.4

Therfore, we can write the length of the longer side is 5.7\ cm

8 0
3 years ago
Is there any other euations that can apply to it
shutvik [7]
I don’t understand apply to what?
5 0
3 years ago
Help pls due soon!!!!!
S_A_V [24]
Each of the squares is 1 so that’s 37 plus 8 half’s which is 4 so 37 + 4 = 41
4 0
3 years ago
Read 2 more answers
-5|4y-11|-3=12<br> Please answer with the steps
iren [92.7K]
-5║4y-11║-3=12
-5║4y-11║-3 +3=12+3
- 5║4y-11║=15
-5/5║4y-11║=15/-5
║4y-11║=-3

4y-11=-3 -5║4y-11║-3=12
4y-11+11=-3+11 -5║4(2)-11║-3=12
4y=8 -5║-3║-3=12
4y/4=8/4 -5 (3)-3=12
y=2 -18≠12

4y-11=3 -5║4y-11║-3=12
4y-11+11=3+11 -5║4(7/2)-11║-3=12
4y=14 -5(3)-3=12
4y/4=14/4 -18≠ 12
y=7/2

No solutions









3 0
3 years ago
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