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slega [8]
2 years ago
13

Determine which function has the greatest rate of change as x approaches infinity.

Mathematics
1 answer:
Mekhanik [1.2K]2 years ago
3 0

Answer: h(x) = 3*x^2 - 7*x + 8

Step-by-step explanation:

The rate of change of a function is equal to the derivate:

remember that a derivate of the form:

k(x) = a*x^n is k'(x) = n*a*x^(n-1)

Then we have:

f(x) = 2*x - 10

f'(x) = 1*2* = 2

g(x) = 16*x - 4

g'(x) = 1*16 = 16

h(x) = 3*x^2 - 7*x + 8

h'(x) = 2*3*x - 1*7 = 6*x - 7

So the only that increases as x increases is h(x), this means that the greates rate of change as x approaches inffinity is the rate of change of h(x)

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kiruha [24]
I believe you’re correct.

y = 3x - 6
8 0
3 years ago
5. Find the general solution to y'''-y''+4y'-4y = 0
CaHeK987 [17]

For any equation,

a_ny^(n)+\dots+a_1y'+a_0y=0

assume solution of a form, e^{yt}

Which leads to,

(e^{yt})'''-(e^{yt})''+4(e^{yt})'-4e^{yt}=0

Simplify to,

e^{yt}(y^3-y^2+4y-4)=0

Then find solutions,

\underline{y_1=1}, \underline{y_2=2i}, \underline{y_3=-2i}

For non repeated real root y, we have a form of,

y_1=c_1e^t

Following up,

For two non repeated complex roots y_2\neq y_3 where,

y_2=a+bi

and,

y_3=a-bi

the general solution has a form of,

y=e^{at}(c_2\cos(bt)+c_3\sin(bt))

Or in this case,

y=e^0(c_2\cos(2t)+c_3\sin(2t))

Now we just refine and get,

\boxed{y=c_1e^t+c_2\cos(2t)+c_3\sin(2t)}

Hope this helps.

r3t40

5 0
3 years ago
You have 19 shirts to choose from, 5 pants, and 2 pairs of shoes. How many different outfits can you make?
Yanka [14]
if this is a homework question, they probably mean the pedestrian 20 outfit answer.
5 0
2 years ago
Write an equation in point-slope form of a line that has a slope of 2/3 and
Serggg [28]

Answer:

y= 2/3x -1

Step-by-step explanation:

Ok so basically we want to put it in the form y=mx+b where m is 2/3 and passes through the point (9,5). So sub in the x and y of the point in brackets into the equation. 5= 2/3(9) + b and solve for b so b = -1. Therefore the equation is y=2/3x -1

5 0
2 years ago
Rachel hikes at a steady rate from a ranger station to a campground that is 20 mi away. After 2 h, she is 13 mi from the campgro
Angelina_Jolie [31]

Answer:

-3.5

The distance Rachel covers per hour is 3.5 miles

Step-by-step explanation:

After 2 hours, she is 13 miles from the campground.

After 4 hours, she is 6 miles from the campground.

Let x be the number of hours, y be the number of miles from the campground, then we have two points (2,13) and (4,6).

The equation of the line passing through the points (x_1,y_1) and (x_2,y_2) is

y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)

Substitute:

x_1=2\\ \\y_1=13\\ \\x_2=4\\ \\y_2=6

Hence,

y-13=\dfrac{6-13}{4-2}(x-2)\\ \\y-13=-3.5(x-2)\\ \\y=-3.5x+7+13\\ \\y=-3.5x+20

The slope of the line is -3.5 and it represents that  the distance Rachel covers per hour is 3.5 miles.

8 0
3 years ago
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