For this case we have the following functions:
h (x) = 2x - 5
t (x) = 6x + 4
Part A: (h + t) (x)
(h + t) (x) = h (x) + t (x)
(h + t) (x) = (2x - 5) + (6x + 4)
(h + t) (x) = 8x - 1
Part B: (h ⋅ t) (x)
(h ⋅ t) (x) = h (x) * t (x)
(h ⋅ t) (x) = (2x - 5) * (6x + 4)
(h ⋅ t) (x) = 12x ^ 2 + 8x - 30x - 20
(h ⋅ t) (x) = 12x ^ 2 - 22x - 20
Part C: h [t (x)]
h [t (x)] = 2 (6x + 4) - 5
h [t (x)] = 12x + 8 - 5
h [t (x)] = 12x + 3
Answer:
2 students
Step-by-step explanation:
First, you find the number of students eating either salads and sandwiches. Then, you add the number of students eating salads and sandwiches together. Finally, you will subtract that number from the 12 total students
<h3>2/3 * 12/1 = 8 (sandwiches)</h3><h3>1/6 * 12/1 = 2 (salads)</h3><h3>8 + 2 = 10 (combined)</h3><h3>12 - 10 = 2 students</h3><h3 />
D
Remember starts at zero slope is up 4 right 1
Y= 4/1x+0
Y=4x
Where is the number line I can't solve without it
