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MArishka [77]
2 years ago
15

Using front-end estimation, find a reasonable estimate of:

Mathematics
2 answers:
Citrus2011 [14]2 years ago
5 0

Answer:

21,000

Step-by-step explanation:

front end estimation requires you to take the front / first digit of each number in this expression and round.

if you don't know how to round, basically you take the next digit after the first one, (in 719 you take the 1) and determine if that's below or above 5. If below, then keep the original first number. If above, add one more to the first digit. If the number is five itself, it is most common to round up (so add one).

like 425 would round to just 400; and 676 would round to 700.

multiply  700 and 30

youd get 21000

Eva8 [605]2 years ago
4 0
Answer: 719• 26 is going to be 21,000
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A civil engineer is analyzing the compressive strength of concrete. Compressive strength is normally distributed with A random s
wel

Answer:

95%: (3278.354 ; 3270.083)

99% : (3221.646 ; 3278.354)

Step-by-step explanation:

Given :

Sample size, n = 12

Mean, xbar = 3250

Sample standard deviation = √1000

The 95% confidence interval :

Mean ± Margin of error

Margin of Error = Tcritical * s/√n

Tcritical at 0.05, df=12-1 = 11 ;

Tcritical at 95% = 2.20

Hence,

Margin of Error = (2.20 * √1000/√12) = 20.083

Confidence interval : 3250 ± 20.083

Lower boundary = 3250 - 20.083 = 3229.917

Upper boundary = 3250 + 20.083 = 3270.083

2.)

The 99% confidence interval :

Mean ± Margin of error

Margin of Error = Tcritical * s/√n

Tcritical at 0.01, df=12-1 = 11 ;

Tcritical at 99% = 3.106

Hence,

Margin of Error = (3.106 * √1000/√12) = 28.354

Confidence interval : 3250 ± 28.354

Lower boundary = 3250 - 28.354 = 3221.646

Upper boundary = 3250 + 28.354 = 3278.354

3 0
3 years ago
Fill in the box to rewrite the expression 5x + 10<br> using the GCF.<br> 5x + 10 = (<br> x) + (5 •
zvonat [6]
The GCF is 5 so the new expression would be: 5(x+2)
7 0
2 years ago
Which box plot represents a set of data that has the least mean absolute deviation?
steposvetlana [31]

Answer:

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Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Use distributive property to model the product on the grid. .record the product 4*12=48
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4 0
3 years ago
If the product of two positive fractions a and b is 15/56, find three pairs of possible values for a and b
Andrews [41]

Answer:

First possible pairs = (3/7)*(5/8) = 15/56

second possible pairs = (3/4)*(5/14) = 15/56

third possible pairs = (1/2)*(15/28) = 15/56

Step-by-step explanation:

According to the question,

a x b = 15/56

three possible pairs will be as follows:

Before proceeding to make possible pairs, we have to know the prime factorization of the numbers -

15 = 1, 3, 5, 15

56 = 1, 2, 4, 7, 8, 14, 28, 56

As we need three possible pairs, we have to check which pairs take us to 15/56. Again, since the fraction is positive, therefore, the fractions will be proper. Therefore, 3/2, or 5/4 will not be counted. Therefore,

First possible pairs = (3/7)*(5/8) = 15/56

second possible pairs = (3/4)*(5/14) = 15/56

third possible pairs = (1/2)*(15/28) = 15/56

fourth possible pairs = (3/8)*(5/7) = 15/56

So, we can get those four possible pairs. Among those, first 3 pairs are different. Therefore, those are possible pairs.

4 0
3 years ago
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