Question

Someone please help me with problem #7 !!!

Answer 1

Answer: b and d

Step-by-step explanation:

Since the roots are x=2 and x=6, we can write the equation as

$f(x)=a(x-2)(x-6)$

Substituting in the coordinates of the vertex,

$-4=a(4-2)(4-6)\\\\-4=-4a\\\\a=1$

So, the equation is $f(x)=(x-2)(x-6)$

On expanding, we get $f(x)=x^2 - 8x+12$