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marusya05 [52]
2 years ago
15

Someone please help me with problem #7 !!!

Mathematics
1 answer:
ser-zykov [4K]2 years ago
3 0

Answer: b and d

Step-by-step explanation:

Since the roots are x=2 and x=6, we can write the equation as

f(x)=a(x-2)(x-6)

Substituting in the coordinates of the vertex,

-4=a(4-2)(4-6)\\\\-4=-4a\\\\a=1

So, the equation is f(x)=(x-2)(x-6)

On expanding, we get f(x)=x^2 - 8x+12

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What is the initial value of the function represented by this graph? (1 point) A coordinate grid is shown with x- and y-axes lab
solmaris [256]

Answer:

7

Step-by-step explanation:

got it right on the test

4 0
3 years ago
Can you solve this? I need help. I don't understand.
ZanzabumX [31]

Answer:

2 sqrt(5) OR 4.5

Step-by-step explanation:

You have to know Pythagorean theorem to solve this question.

a^2 + b^2 = c^2

To use this theorem you have to have a right triangle. There are two right triangles in your image. The lower (larger) one has two sides labeled, so you can use Pythagorean thm to find the third side. There's a short cut, bc some right triangles have easy-to-memorize lengths of the sides. 3-4-5 is one of these number sets. A multiple of this is 6-8-10. We could've solved:

b^2 + 8^2 = 10^2

But it would've come out the same. The unlabeled side is 6.

We can use the 6 and the 4 on the smaller right triangle and use the Pythagorean thm again to solve for x.

4^2 + x^2 = 6^2

16 + x^2 = 36 subtract 16 from both sides.

x^2 = 20

Take the square root of both sides.

sqrt (x^2) = sqrt 20

x = 2 sqrt(5) which is approximately 4.472.

2 sqrt(5) is an exact answer if that is what they are asking for. 4.472 is an approximation to the nearest thousandth. It would be 4.47 to the nearest hundredth or 4.5 to the nearest tenth.

8 0
2 years ago
I’m confused on this answer anyone know it?
slamgirl [31]

Answer:

y=\frac{26}{7},\:x=-\frac{15}{7}

Step-by-step explanation:

\begin{bmatrix}4x+5y=10\\ -2x+y=8\end{bmatrix}\\\\\begin{bmatrix}-2\cdot \frac{10-5y}{4}+y=8\end{bmatrix}\\\\

-5+\frac{7y}{2}=8\\\\\mathrm{Multiply\:both\:sides\:by\:}2\\-5\cdot \:2+\frac{7y}{2}\cdot \:2=8\cdot \:2\\-10+7y=16\\y=\frac{26}{7}\\

\mathrm{For\:}x=\frac{10-5y}{4}\\\mathrm{Subsititute\:}y=\frac{26}{7}\\x=\frac{10-5\cdot \frac{26}{7}}{4}\\\\

x=-\frac{15}{7}\\

7 0
3 years ago
GUYS AM I CORRECT?? I WILL MARK U BRAINLEST IF I GET IT RIGHT
Paul [167]

Answer:

Yes you are correct.

6 0
3 years ago
Read 2 more answers
20 - 4 { 20÷ 7 ( 7 - 3 )}​
hodyreva [135]

20 -4 { 20÷ 7 ( 7 - 3 )}

20 -4 { 20 ÷ 7 * 4 }

20 - 4 { 2.85 * 4 }

16 * 11.42

182.85

4 0
3 years ago
Read 2 more answers
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