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bogdanovich [222]

3 years ago

13

How high is the end of the ladder against the building? Round to the nearest tenth if necessary.

1 answer:

kifflom [539]3 years ago

6 0

H(ft) = √ (13² - 4²) = 12.4

It is a right-angled triangle and the Pythagorean theorem applies.

THEOREMA (by Pythagoras):
Given a right-angled triangle ABCABC as in the figure, then the relation is valida2 + b2 = c2a2 + b2 = c2where cc is the hypotenuse of the triangle and b, ab, a are the cathets.

h(ft) = √ (13² - 4²) = 12.4

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Please help... I have no clue

muminat

Answer:

OPTION C: Sin C - Cos C = s - r

Step-by-step explanation:

ABC is a right angled triangle. ∠A = 90°, from the figure.

Therefore, BC = hypotenuse, say h

Now, we find the length of AB and AC.

We know that: $\textbf{Sin A} = \frac{\textbf{opp}}{\textbf{hyp}}$

and $\textbf{Cos A} = \frac{\textbf{adj}}{\textbf{hyp}}$

Given, Sin B = r and Cos B = s

⇒ $Sin B = r = \frac{opp}{hyp} = \frac{AC}{BC} = \frac{AC}{h}$

⇒ $\textbf{AC} = \textbf{rh}$

Hence, the length of the side AC = rh

Now, to compute the length of AB, we use Cos B.

$Cos B = s = \frac{adj}{hyp} = \frac{AB}{BC} = \frac{AB}{h}$

⇒ $\textbf{AB} = \textbf{sh}$

Hence, the length of the side AB = sh

Now, we are asked to compute Sin C - Cos C.

$Sin C = \frac{opp}{hyp}$

⇒ $Sin C = \frac{AB}{BC}$

$= \frac{sh}{h}$

= s

Sin C = s

$Cos C = \frac{adj}{hyp}$

$\implies Cos C = \frac{AC}{BC}$

⇒ Cos C = $\frac{rh}{h}$

Therefore, Cos C = r

So, Sin C - Cos C = s - r, which is OPTION C and is the right answer.

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Answer:

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Step-by-step explanation:

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