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bogdanovich [222]
3 years ago
13

How high is the end of the ladder against the building? Round to the nearest tenth if necessary.

Mathematics
1 answer:
kifflom [539]3 years ago
6 0
H(ft) = √ (13² - 4²) = 12.4

It is a right-angled triangle and the Pythagorean theorem applies.

THEOREMA (by Pythagoras):
Given a right-angled triangle ABCABC as in the figure, then the relation is valida2 + b2 = c2a2 + b2 = c2where cc is the hypotenuse of the triangle and b, ab, a are the cathets.

h(ft) = √ (13² - 4²) = 12.4



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\cos(A)  +  \cos( B )  +  \cos(C)  \\  = 2 \cos( \frac{A + B}{2} )  \cos( \frac{ A- B}{2} )  + 1 - 2 { \sin }^{2}  \frac{C}{2}  \\  = 1 + 2\cos( \frac{\pi - C}{2} )   \cos( \frac{A - B}{2} )  - 2 { \sin }^{2}  \frac{C}{2}  \\  = 1 + 2 \sin \frac{C}{2}  \cos( \frac{A - B}{2} )  - 2 { \sin }^{2}  \frac{C}{2}  \\  = 1 + 2 \sin \frac{C}{2} [ \cos( \frac{A - B}{2} ) - \sin \frac{C}{2}]  \\  =  1 + 2 \sin \frac{C}{2} [ \cos( \frac{A - B}{2} ) - \cos( \frac{A  +  B}{2} )] \\  = 1 + 2 \sin\frac{C}{2} \times 2 \sin( \frac{ \frac{A + B}{2}  +\frac{A  -  B}{2} }{2} )  \sin( \frac{ \frac{A + B}{2}   - \frac{A  -  B}{2} }{2} )  \\  = 1 + 4 \sin \frac{A}{2}  \sin \frac{B}{2}  \sin \frac{C}{2}

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3 years ago
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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

The answer in the procedure

Step-by-step explanation:

we have

2x-3y=-1 ----> equation A

3x+3y=26 --> equation B

Solve the system by elimination

Adds equation A and equation B

2x-3y=-1

3x+3y=26

----------------

2x+3x=-1+26

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x=25/5

x=5

Find the value of y

substitute the value of x in equation A or equation B and solve for y

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3y=10+1

y=11/3

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