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3 years ago

12

Work out the value of 10^2-4^3 .give your answer as a power of 6

2 answers:

Fittoniya [83]3 years ago

7 0

Answer:

Answer: 6^2

Step-by-step explanation:

Givens

Express the integers raised to a power as integers.
10^2 = 100
4^3 = 64

Solution

Subtract 64 (which is 4^3) from 100. See if what is left is a power of 6
100 - 64 = 36 Yes the remainder is 36
36 = 6*6 = 6^2

erastovalidia [21]3 years ago

7 0

Answer:

6^2

Step-by-step explanation:

10^2-4^3

PEMDAS says powers first

100 - 64

Subtract

36

We know that 36 is a perfect square

6*6

6^2

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HURRYYYYYYYYY!! What is the equation of the quadratic function with a vertex at (2, 25) and an x-intercept at (7,0)?

tangare [24]

Answer:

$y=-(x-7)(x+3)$

which is none of the choices provided.

Are you sure the question is right or even the choices?

You can even write it as:

$y=-(x+3)(x-7)$ but this is still not a choice.

Step-by-step explanation:

The vertex form of a quadratic is $y=a(x-h)^2+k$ .

This is called vertex form because it gives you the vertex is $(h,k)$ .

We are given that $(h,k)=(2,25)$ which makes our equation:

$y=a(x-2)^2+25$ .

We can find the value of $a$ by plugging in the x-intercept (7,0) for $(x,y)$ into:

$y=a(x-2)^2+25$

$0=a(7-2)^2+25$

$0=a(5)^2+25$

Subtract 25 on both sides:

$-25=a(5)^2$

$-25=a(25)$

Divide both sides by 25:

$\frac{-25}{25}=a$

$-1=a$ .

So the equation for the quadratic is:

$y=-1(x-2)^2+25$

Let's put this into factored form since all the choices are in factored form.

This will require us to multiply the (x-2)(x-2) out:

$y=-1(x-2)(x-2)+25$

$y=-1(x^2-2x-2x+4)+25$

$y=-1(x^2-4x+4)+25$

$y=-x^2+4x-4+25$

$y=-x^2+4x+21$

Factor out -1:

$y=-(x^2-4x-21)$

WE need to find two numbers that multiply to be -21 and add to be -4:

$y=-(x-7)(x+3)$

8 0

3 years ago

Read 2 more answers

Evaluate the expression 5(-3) using a number line.

MArishka [77]

Answer: -15

Step-by-step explanation:

7 0

2 years ago

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I NEED HELP!! please show all work

PtichkaEL [24]

Take the logarithm of both sides. The base of the logarithm doesn't matter.

$4^{5x} = 3^{x-2}$

$\implies \log 4^{5x} = \log 3^{x-2}$

Drop the exponents:

$\implies 5x \log 4 = (x-2) \log 3$

Expand the right side:

$\implies 5x \log 4 = x \log 3 - 2 \log 3$

Move the terms containing <em>x</em> to the left side and factor out <em>x</em> :

$\implies 5x \log 4 - x \log 3 = - 2 \log 3$

$\implies x (5 \log 4 - \log 3) = - 2 \log 3$

Solve for <em>x</em> by dividing boths ides by 5 log(4) - log(3) :

$\implies \boxed{x = -\dfrac{ 2 \log 3 }{ 5 \log 4 - \log 3 }}$

You can stop there, or continue simplifying the solution by using properties of logarithms:

$\implies x = -\dfrac{ \log 3^2 }{ \log 4^5 - \log 3 }$

$\implies x = -\dfrac{ \log 9 }{ \log 1024 - \log 3 }$

$\implies \boxed{x = -\dfrac{ \log 9 }{ \log \frac{1024}3 }}$

You can condense the solution further using the change-of-base identity,

$\implies \boxed{x = -\log_{\frac{1024}3}9}$

5 0

3 years ago

A fair die with sides numbered 1, 2, 3, 4, 5, and 6 is to be rolled until a number greater than 4 first appears. what is the pro

AnnyKZ [126]

First two rolls have to be 1-4 that is 2/3 chance twice and the third can be 4or 5
2/3*2/3*1/3 + the chance that the fourth is the 5 or 6.
2/3*2/3*2/3*1/3

So the solution is : P=2/3*2/3*1/3 + 2/3*2/3*2/3*1/3

7 0

4 years ago

Which equation is equivalent to 24x = 8x-3?

Elena-2011 [213]

Answer:

uh maybe 16x= -3 or x= -3/16

Step-by-step explanation:

I'm so sorry if this is wrong or not what you're looking for

3 0

4 years ago

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