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enyata [817]
3 years ago
12

Work out the value of 10^2-4^3 .give your answer as a power of 6

Mathematics
2 answers:
Fittoniya [83]3 years ago
7 0

Answer:

Answer: 6^2

Step-by-step explanation:

Givens

  • Express the integers raised to a power as integers.
  • 10^2 = 100
  • 4^3 = 64

Solution

  • Subtract 64 (which is 4^3) from 100. See if what is left is a power of  6
  • 100 - 64 = 36      Yes the remainder is 36
  • 36 = 6*6 = 6^2
erastovalidia [21]3 years ago
7 0

Answer:

6^2

Step-by-step explanation:

10^2-4^3

PEMDAS says powers first

100 - 64

Subtract

36

We know that 36 is a perfect square

6*6

6^2

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Chen completed the division problem below.
alekssr [168]

<u>Answer:</u>

B. He multiplied the dividend by 100 instead of 10.

<u>Step-by-step explanation:</u>

Chen had to divide 1.926 by 0.9. To make it easier to divide, he thought of multiplying both the dividend and the divisor by 10.

Chen multiplied the divisor by 10 but mistakenly multiplied the dividend by 100 instead of 10.

So his whole division problem was changed.

Therefore, the correct answer option is B. He multiplied the dividend by 100 instead of 10.

6 0
3 years ago
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What expression is equivalent to the expression (4x+12) + 7x?
pochemuha

Answer:

11x + 12

Step-by-step explanation:

( 4x + 12 ) + 7x

Remove parentheses.

= 4x + 12 + 7x

Group like terms.

= 4x + 7x + 12

Add similar elements: 4x + 7x = 11x

= 11x + 12

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3 years ago
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OT bisects ∠DOG. Find the measure of ∠DOG if ∠DOT = 4x + 4 and ∠TOG = 5x – 3
g100num [7]

Answer:

\huge\boxed{64^o}

Step-by-step explanation:

If OT is bisects ∠DOG, then m∠DOT = m∠TOG. Therefore

4x+4=5x-3    |<em>subtract 4 from both sides</em>

<em />4x+4-4=5x-3-4\\\\4x=5x-7<em>|subtract 5x from both sides</em>

<em />4x-5x=5x-5x-7\\\\-x=-7<em>|change the signs</em>

<em />x=7<em />

Calculate the measure of ∠DOG

m∠DOG = 2(m∠DOT)

m\angle DOG=2(4\cdot7+4)=2(28+4)=2(32)=64

6 0
3 years ago
The sum of an infinite geometric series is three times the first term. Find the common ratio of this series.
adelina 88 [10]

Answer:

\frac{2}{3}

Step-by-step explanation:

The sum of an  infinite geometric series is expressed according to the formula;

S_\infty = \dfrac{a}{1-r} where;

a is the first term of the series

r is the common ratio

If the sum of an infinite geometric series is three times the first term, this is expressed as S_\infty = 3a

Substitute S_\infty = 3a into the formula above to get the common ratio r;

3a = \dfrac{a}{1-r} \\\\

cross \ multiply\\\\3a(1-r) = a\\\\3(1-r) = 1\\

open the parenthesis

3 - 3r = 1\\\\

subtract 3 from both sides

3 - 3r -3= 1-3\\\\-3r = -2\\\\r = \frac{2}{3}

<em>Hence the common ratio of this series is </em>\frac{2}{3}<em></em>

3 0
3 years ago
Pls help i will give brainliest
Vladimir79 [104]

Answer:

the thrid one

Step-by-step explanation:

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