All categories

2 years ago

Help help help help help

Mathematics

2 answers:

Norma-Jean [14]2 years ago

5 0

Step-by-step explanation:

volume = [(15×11)+(½×15×8)] x 12

= (165+60) x 12

= 225×12

= 2,700 cm³

kow [346]2 years ago

4 0

Answer:

31350cm^3

Step-by-step explanation:

1/2(5 x 9.5 x 11)

= 261.25

261.25 x 12

= 3135

3135 x 10 = 3135cm^3

<u><em>Please mark as brainliest if answer is right </em></u>

Have a great day, be safe and healthy

Thank u

You might be interested in

Which number represents 593 rounded to the nearest ten 600 610 603 590

Readme [11.4K]

Answer:

590 would be your answer

Step-by-step explanation:

3 0

3 years ago

In a survey of 3,200 people who owned a certain type of car, 960 said they would buy that type of car again. What percent of th

pshichka [43]

Answer: let

Total number of those who took part in the survey (T)=3200

Those who were satisfied (t)=960

Percentage of those who were satisfied (S)=(t/T)*100

S=(960/3200)*100

S=30%

Therefore only 30% were satisfied

Step-by-step explanation:

8 0

3 years ago

Suppose you want purchase a new bicycle without using credit. The cost of the bike

9966 [12]

About 5.5 months. please mark me brainliest. have a great day and good luck with school

8 0

3 years ago

Read 2 more answers

I need help ASAP. Please answer this equation! Combine like terms.

Pavel [41]

Step-by-step explanation:

4x+ 5x - 5 +6 +4y^3- 2y^3- 5y^3

9x + 1 + 64y - 8y - 125y

9x + 1 - 69y

8 0

3 years ago

Andrew is about to leave for school. If he walks at a speed of 50 meters per minute, he will arrive 3 minutes after the bell rin

Mariana [72]

Answer:

The answer is: 13 minutes

Step-by-step explanation:

First Let us form equations with the statements in the two scenario

$time=\frac{distance}{speed}$

Let the time in which the bell rings be 'x'

1. If Andrew walks (50 meters/minute), he arrives 3 minutes after the bell rings. Therefore the time of arrival at this speed = (3 + x) minutes

$3 + x =\frac{distance}{50}\\distance = 50(3+x) - - - - - (1)$

2. If Andrew runs (80 meters/minute), he arrives 3 minutes before the bell rings. Therefore the time taken to travel the distance = (x - 3) minutes

$x - 3 = \frac{distance}{80} \\distance = 80(x-3) - - - - - (2)$

In both cases, the same distance is travelled, therefore, equation (1) = equation (2)

$50(3+x)=80(x-3)$

$150 +50x=80x-240\\$

Next, collecting like terms:

$150 + 240 = 80x - 50x\\390 = 30x\\30x = 390\\$

dividing both sides by 3:

x = 390÷30 = 13

∴ x = 13 minutes

7 0

3 years ago