Answer:
i thinks the answer is the fourth, which an= 3-2(n-1)
y=mx+b is the equation of a line;
m=slope , b= y-intercept
You can find the slope with this following equation: (y(2)-y(1))/(x(2)-x(1))
In this case the points are (0,4) and (-2,-3). The first set being (0,4) and the second (-2,-3). This means (0,4) can be expressed as (x(1),y(1)) and (-2,-3) expressed as (x(2),y(2)). Plugging these numbers into the slope equation gives us: (-3-4)/(-2-0) = -7/-2 = 7/2.
m= 7/2 ; so we have : y= (7/2)x+b
We are give a set of points which it passes through, we can simply plug them in:
4 = (7/2)(0)+b (0 is the x and 4 is the y)
We get 4 = 0 +b .... 4=b
our final equation is : y=(7/2)x+4
Find the critical points of 
:
All three points lie within 
, and 
takes on values of
Now check for extrema on the boundary of . Convert to polar coordinates:
Find the critical points of 
:
where 
is any integer. There are some redundant critical points, so we'll just consider 
, which gives
which gives values of
So altogether, has an absolute maximum of 65/16 at the points (0, -1/2) and (0, 1/2), and an absolute minimum of 3 at (-1, 0).
The composite is 4 .
I hope this helps and please mark as branilyest I need 4 more to level up in rank.
Turtle14526
Answer:
x = 13.5
y = 7
(13.5,7)
what the solution means is that (13.5,7) would be the point at which the two lines, x+y=20.5 and x-y=6.5, would intersect
Step-by-step explanation:
x + y = 20.5
x - y = 6.5
if we add the two equations we get:
2x = 27
x = 13.5
y = 20.5 - 13.5
y = 7
solution as an ordered pair:
(13.5,7)
What the solution means is that (13.5,7) would be the point at which the two lines, x+y=20.5 and x-y=6.5, would intersect
