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2 years ago

10

On a coordinate plane, the coordinates of vertices R and T for a polygon are R(−6, 2) and T(5, 2). What is the length of Side RT

of the polygon?

1 answer:

Rainbow [258]2 years ago

3 0

Use the formula
D=sqrt[ (x2-X1)^2 + (Y2-Y1)^2]

= sqrt(11^2+0^2)=11.

Sqrt means square root.

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Draw the model to show 5.5/5

babunello [35]

This would be easy if you made more sense out of the question.

4 0

2 years ago

Solve the following system of equations. Express your answer as an ordered pair in the format (a,

choli [55]

The second equation is <span>-5-2y=2, then
</span>
<span>-2y=2-(-5),
</span>
-2y=2+5,
-2y=7,
y=7÷(-2),
y=-3.5.
The first equation is 2x+5y=16, subtitude y=-3.5 in this equation, then
2x+5·(-3.5)=16,
2x-17.5=16,
2x=16-(-17.5),
2x=16+17.5,
2x=33.5,
x=33.5÷2,
x=16.75.
Answer: (16.75,-3.5)

8 0

3 years ago

Read 2 more answers

4 (x+2) as a word phrase

ycow [4]

Four times the sum of x and two

8 0

3 years ago

Read 2 more answers

If the geometric mean of a and 34 is 6 sqrt(17) find the value of a

Alborosie

Using the geometric mean concept, it is found that the value of a is 18.

----------------------

The geometric mean, of a data-set of n elements, $(n_1, n_2, ..., n_n)$ , is given by:

$G = \sqrt[n]{n_1 \times n_2 \times ... \times n_n}$

That is, the nth root of the multiplication of all elements.

----------------------

In this question:

Two elements(n = 2), a and 34.
$G = 6\sqrt{17}$

Thus:

$\sqrt{34a} = 6\sqrt{17}$

We find the square of each side, so:

$(\sqrt{34a})^2 = (6\sqrt{17})^2$

$34a = 36\times17$

Simplifying both sides by 17:

$2a = 36$

$a = \frac{36}{2}$

$a = 18$

The value of a is 18.

A similar example is given at brainly.com/question/15010240

3 0

3 years ago

184=1/2x(8.5+14.5)<br><br> how do i cancel out the fraction?

Olin [163]

184 = ¹/₂x(8.5 + 14.5)
184 = ¹/₂(23)
<u>184</u> = <u>11¹/₂x
</u>11¹/₂ 11¹/₂
16 = x

7 0

3 years ago