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babunello [35]
3 years ago
13

Copper has an atomic number of 29. that means that there are 29 protons in the nucleus of each copper atom. That's what the atom

ic number is; the number of protons in an atom of a certain element.If one copper atom contains 29 protons, how many copper atoms could you make out of 174 protons?
Chemistry
1 answer:
denis-greek [22]3 years ago
7 0
The answer is 6....... 174÷29=6
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A student obtains a 10.0g sample of a white powder labeled as BaCl2. After completely dissolving the powder in 50.0mL of distill
LekaFEV [45]

Answer:

Whether barium chloride solution was pure

Explanation:

We may answer whether barium chloride was pure. The sequence of this experiment might be depicted by the following balanced chemical equations:

BaCl_2 (aq)\rightarrow Ba^{2+} (aq) + 2 Cl^- (aq)

Ba^{2+} (aq) + SO_4^{2-} (aq)\rightarrow BaSO_4 (s)

Having a total sample of 10.0 grams, we would firstly find the mass percentage of barium in barium chloride:

\omega_{Ba^{2+}} = \frac{M_{Ba}}{M_{BaCl_2}} = \frac{137.327 g/mol}{208.23 g/mol\cdot 100\% = 65.95 \%

This means in 10.0 g, we have a total of:

m_{Ba^{2+}} = 10.0 g\cdot 0.6595 = 6.595 g of barium cations.

The precipitate is then formed and we measure its mass. Having its mass determined, we'll firstly find the percentage of barium in barium sulfate using the same approach:

\omega_{Ba} = \frac{137.327 g/mol}{233.38 g/mol}\cdot 100\% = 58.84 \%

Multiplying the mass we obtained by the fraction of barium will yield mass of barium in barium sulfate. Then:

  • if this number is equal to 6.595 g, we have a pure sample of barium chloride;
  • if this number is lower than 6.595 g, this means we have an impure sample of barium chloride, as we were only able to precipitate a fraction of 6.595 g.
3 0
3 years ago
HELP MEEEE ASAP!!! Answer these questions based on what you learned from the passage. You can assume any body structure comes fr
erica [24]

Answer:

1.Legs

2.Arms and hands

3.Armor

4.Skeletal

5.Carpenters

6.Brain

7.Skin

8.Blood

Explanation:

You can google dem and it will show you all the answers

4 0
4 years ago
For the first order process: AB The half-life of A is 62.1 seconds. If a sample of A initially has 250.0 g, what mass (in g) of
vodomira [7]

<u>Answer:</u> The mass of sample A after given time is 99.05 g.

<u>Explanation:</u>

All the radioactive reactions follows first order kinetics.

The equation used to calculate half life for first order kinetics:

t_{1/2}=\frac{0.693}{k}

We are given:

t_{1/2}=62.1s

Putting values in above equation, we get:

k=\frac{0.693}{62.1}=0.011s^{-1}

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}

where,

k = rate constant = 0.011s^{-1}

t = time taken for decay process = 84.2 s

[A_o] = initial amount of the reactant = 250 g

[A] = amount left after decay process =  ?

Putting values in above equation, we get:

0.011s^{-1}=\frac{2.303}{84.2s}\log\frac{250}{[A]}

[A]=99.05g

Hence, the mass of sample A after given time is 99.05 g.

8 0
3 years ago
Which body system includes the lungs?m​
Zanzabum

Answer: <u>The respiratory system </u>

Explanation: It includes the nose, mouth, throat, voice box, windpipe, and lungs. Air enters the respiratory system through the nose or the mouth.

4 0
3 years ago
Pls help question 2 ill attach a picture​
Finger [1]

Answer:

X 154

Check solution in explanation

Explanation:

Average atomic mass = ( mass 1× abudance) + ( mass 2× abudance)+ ( mass 3× abudance) / 100

(149×13.8)+(152×44.9) +(154×41.3)/100

2056.2 + 6824.8 + 6360.2/100

=152.412

8 0
3 years ago
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