Answer:
31.7 °C
Explanation:
Charles law states that for volume of a gas is directly proportional to the absolute temperature for a fixed amount of gas at constant pressure
we can use the following equation
V1/T1 = V2/T2
where V1 is volume and T1 is temperature at first instance
V2 is volume and T2 is temperature at second instance
temperature should be in kelvin scale
T1 - 0 °C + 273 = 273 K
substituting the values in the equation
22.4 L / 273 K = 25.0 L / T2
T2 = 304.7 K
temperature in celcius is - 304.7 K - 273 = 31.7 °C
the gas must be 31.7 °C to reach a volume of 25.0 L
[Ar] 4s²
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Hope that helps
<span>The concentration of pb2+ = 1.00mg/ml
Diluted Solution is 6.0 x 102 ml = 612 ml
Volume of the concentration of pb2+ is 0.054 mg/l is v
(vL)(1.00mg/ml) = (.612L)(0.054mg/l)
Volume = 0.033048L
Volume of the concentration of pb2+ is 0.054 mg/l = 33.048 ml.</span>
Answer in file below
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Temperature of gas at volume of 950 cm³ is 368.14K or 94.99⁰c.
- Volume is the amount of space a three-dimensional object takes up, expressed in cubic units.
- units of volume are mL, liter, cm³ or m³.
Given,
in this question, volume occupied by gas at 10.9⁰c is 733cm³.
we have to find out temperature at which gas occupies volume of 950 cm³.
First, convert temperature from celcius to Kelvin
10.9⁰c = 10.9 + 273.15 = 284.05 K
By equation or Boyle's Law
P1 x V1 / T1 = P2 x V2 / T2
Pressure is constant here
therefore, V1 / T1 = V2 / T2
here, V1 = 733 cm³
T1 = 284.05 K
V2 = 950 cm³
we have to find out T2
So, 733 / 284.05 = 950 / T2
T2 = 284.05 × 950 / 733 = 368.14 K
= 94. 99⁰c
Therefore the temperature of gas at volume of 950 cm³ is 368.14K or 94.99⁰c.
Learn more about Boyle's Law here:
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