1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Oduvanchick [21]
3 years ago
14

Cu20(s) + C(s) - 2Cu(s) + CO(g)

Chemistry
1 answer:
Romashka-Z-Leto [24]3 years ago
6 0

Answer:

That means Cu2O is limiting reagent and C is excess reagent

Explanation:

Based on the reaction, 1 mole of Cu2O reacts per mole of C. The ratio of reaction is 1:1.

To solve this question we need to convert the mass of each reactant to moles. The reactant with the lower amount of moles is limiting reactant and the excess reactant is the reactant with the higher number of moles.

<em>Moles Cu2O -Molar mass: 143.09 g/mol-</em>

114.2g Cu2O * (1mol / 143.09g) = 0.798 moles Cu2O

<em>Moles C -Molar mass: 12.01g/mol-</em>

11.1g C * (1mol / 12.01g) = 0.924 moles C

<h3>That means Cu2O is limiting reagent and C is excess reagent</h3>

<em> </em>

<em />

You might be interested in
The number of protons plus the number of neutrons in an atom is called its 7 number. for carbon-12, this number is
emmasim [6.3K]
The mass of Carbon-12 is 12.
8 0
3 years ago
PLEASE HELP!!!!!!!
dsp73

Answer: 1. 2Al+3CuCl_2\rightarrow 2AlCl_3+3Cu

2. 3 moles of CuCl_2 : 2 moles of Al

3. 0.33 moles of CuCl_2 : 0.92 moles of Al

4. CuCl_2 is the limiting reagent and Al is the excess reagent.

5. Theoretical yield of AlCl_3 is 29.3 g

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} Al=\frac{25.0g}{27g/mol}=0.92moles

\text{Moles of} CuCl_2=\frac{45.0g}{134g/mol}=0.33moles

The balanced chemical equation is:

2Al+3CuCl_2\rightarrow 2AlCl_3+3Cu  

According to stoichiometry :

3 moles of CuCl_2 require = 2 moles of Al

Thus 0.33 moles of CuCl_2 will require=\frac{2}{3}\times 0.33=0.22moles  of Al

Thus CuCl_2 is the limiting reagent as it limits the formation of product and Al is the excess reagent.

As 3 moles of CuCl_2 give = 2 moles of AlCl_3

Thus 0.33 moles of CuCl_2 give =\frac{2}{3}\times 0.33=0.22moles  of AlCl_3

Theoretical yield of AlCl_3=moles\times {\text {Molar mass}}=0.22moles\times 133.34g/mol=29.3

Thus 29.3 g of aluminium chloride is formed.

5 0
3 years ago
Which of the following is an electrolyte?<br><br> a. PbCl2<br> b. MgS<br> c. HNO3<br> d. Al2(Cr2O7)3
Phoenix [80]

Answer: A: PbCl2

Hope dis helps!

8 0
3 years ago
Hydrogen is a pure substance represented by the chemical symbol H. Which of the following best describes hydrogen?
Soloha48 [4]

Answer:

B is the answer

Explanation:

Because it a molecular mass of one

3 0
3 years ago
If an ideal gas has a pressure of 5.49 atm, a temperature of 88.78 °c, and has a volume of 22.03 l, how many moles of gas are in
kirza4 [7]
N = (PV)/RT
(T = 88.78 + 273 = 361.78K)
(R = 22.4/273 = 0.082)
= (5.49 x 22.03)/(0.082 x 361.78) = ?
Put it into the calculator. It's hard to do that on a mobile phone.
7 0
4 years ago
Other questions:
  • The water lattice: a. is formed from hydrophobic bonds. b. causes ice to be denser than water. c. causes water to have a relativ
    13·1 answer
  • True or False: Particles that are moving faster have a higher temperature
    10·2 answers
  • At what phase of the cell cycle do the chromosomes coil up tightly?
    11·1 answer
  • ΑC2H6O+βO2 → γC2H4O2+δH2O
    10·1 answer
  • What changes shape but doesn't change volume
    12·1 answer
  • Please help with all 3 parts!
    9·2 answers
  • किसी भी व्यक्ति के पतन का क्या कारण होत है​
    15·1 answer
  • How many grmas of CaCO3 are present in a sample if there are 4. 52 x 10^24 atoms of carbon in that sample?
    15·1 answer
  • Why are there sometimes warm days during a cold winter? (not chemistry, its actually science)
    9·1 answer
  • Which compounds exhibit geometric isomerism? Draw and name the two isomers in each case:(b) 3-hexene
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!