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Burka [1]
4 years ago
14

If a gas is initially at a pressure of nine ATM and a volume at 21 L at a temperature of 253K and the pressure is raise to 15 AT

M and the temperature is raised to 302K what will be the resulting volume of the gas
Chemistry
1 answer:
Tom [10]4 years ago
3 0

Answer:

15.0L

Explanation:

p/v = constan

(9*21)/253 =(15v)/ 302

v = (9*21*302)/(15*253)

v=15.0

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For the reaction so3 + h2o h2so4, calculate the percent yield if 500. g of sulfur trioxide react with excess water to produce 57
Lelu [443]
The %  yield  if  500 g of  sulfur trioxide  reacted  with  excess  water to   produce  575 g  of  sulfuric  acid is calculated using  the  below  formula


%  yield = actual  yield/ theoretical  yield  x100

actual  yield =575 grams
to  calculate  theoretical  yield
find the  moles  of SO3   used =mass/molar  mass
=  500g/   80 g/mol =6.25  moles

SO3+H2O=H2SO4
by   use of  mole ratio  of SO3  :  H2SO4 which  is 1:1  the moles of H2SO4  is  also=  6.25  moles

the theoretical  yield of H2SO4 is therefore =  moles /molar  mass
=  6.25  x98=  612.5 grams

%yield  is therefore= 575 g/612 g   x100=  93.9  %

5 0
3 years ago
Water is a good choice of solvent because it is benign, cheap and readily available. Identify two characteristics that make wate
Mila [183]

Answer:

Two characteristics that make water a good choice for the recrystallization solvent for benzoic acid are

  1. Low solubility for benzoic acid at room temperature
  2. Less expensive

Explanation:

Characteristics of a Good Recrystallization Solvent:

  1. Cheap.
  2. High volatility.
  3. No reaction with substrate to be made pure.
  4. Insoluble impurities should not be dissolced by the olvent at all temperatures.
  5. At room temperature the solvent should have high solubility for soluble impurities well
  6. At  room temperature the substance to be purified should be insoluble in the solvent.

As such water has both low solubility for benzoic acid at room temperature and water is cheap or readily available

3 0
4 years ago
How many mL of 3.0M HCl are needed to make 300.0 mL of a 0.10M HCl?
nalin [4]

Answer:

V₁  = 10 mL

Explanation:

Given data:

Initial volume of HCl = ?

Initial molarity = 3.0 M

Final molarity = 0.10 M

Final volume = 300.0 mL

Solution:

Formula:

M₁V₁  =  M₂V₂

M₁ = Initial molarity

V₁  =  Initial volume of HCl

M₂ =Final molarity

V₂ = Final volume

Now we will put the values.

3.0 M ×V₁  =  0.10 M×300.0 mL

3.0 M ×V₁  = 30 M.mL

V₁  = 30 M.mL /3.0 M

V₁  = 10 mL

3 0
3 years ago
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