If a gas is initially at a pressure of nine ATM and a volume at 21 L at a temperature of 253K and the pressure is raise to 15 AT
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Answer:
V₂ = 0.4 L
Explanation:
<u>Data:</u>
- P₁ (initial pressure) = 500 torr
- V₁ (initial volume) = 0.5 L
- P₂ (final pressure) = 700 torr
<u>Wanted:</u>
- V₂ (final volume)
<u>Equation:</u>
- P₁V₁ = P₂V₂ → V₂ = P₁V₁ / P₂
<u>Solution:</u>
- V₂ =
= 0.3571 L or 0.4 L